Tips on cracking Aptitude Questions on Races and games

1. 3 TIPS on cracking Aptitude Questions on Races and Games

2. Tip #1: Acquaint yourself with the terms Dead Heat Race: A race in which all the contestants reach the Goal at the same time. Start: If A and B are two contestants in a race, such that before the start of the race, A is at the starting point and B is ahead of A by 12 meters, then we say that ‘A gives B a start of 12 meters’. Game: A game of 100, means that the person among the contestants who scores 100 points first is the winner. If A scores 100 points while B scores only 80 points, then we say that 'A can give B 20 points’. This implies that if A actually gave B a start of 20 points, then the contest would result in a dead heat.

3. Tip #2: Assume that the speed or the scoring rate for each player is constant Question: In a game of 100 points, A can give B 20 points and C 28 points. How many points can B give C? Solution: By the time A scores 100 points, B scores only 80 and C scores only 72 points. Let the Scoring Rate of A be Sa. (Scoring Rate = score/ time) Scoring Rate of B, Sb = 80/100 x Sa = 0.8 Sa Scoring Rate of C, Sc = 72/100 x Sa = 0.72 Sa Time taken for B to get 100 points = 100/Sb = 100/ (0.8 x Sa) Score taken by C in this time period = Sc x 100/ (0.8 x Sa) = 72/0.8 = 90 Thus, B can give C 10 points. Question: In a 200 m race A beats B by 35 m or 7 sec. Find A's time over the course. Solution: By the time A completes the race, B is 35m behind A and would take 7 more seconds to complete the race. => B can run 35 m in 7 s. Thus, B’s speed = 35 / 7 = 5 m/s. Time taken by B to finish the race = 200 / 5 = 40 s. Thus, A’s time over the course = (40 – 7)s = 33 s.

4. Tip #3: If A runs x times faster than B, A’s speed is actually 1+x the speed of B. • Question: A runs 1⅔ times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time? • Solution: • Speed of A, Sa = 5/3 x Sb • Let the distance of the course be ‘d’ meters • Time taken by A to cover distance ‘d’ = Time taken by B to cover distance ‘d-80’ • d/[5/3 x Sb] = (d-80)/Sb • 3d = 5d – 400 • 2d = 640 => d = 200m • Question: A runs 1⅔ times faster than B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time? • Solution: • Speed of A, Sa = (1 + 5/3) x Sb = 8/3 x Sb • Let the distance of the course be ‘d’ meters • Time taken by A to cover distance ‘d’ = Time taken by B to cover distance ‘d-80’ • d/[8/3 x Sb] = (d-80)/Sb • 3d = 8d – 640 • 5d = 640 => d = 128m

5. About Us LearningPundits helps Job Seekers make great CVs, master English Grammar and Vocabulary , ace Aptitude Tests , speak fluently in a Group Discussion and perform well in Interviews. We also conduct weekly online contests on Aptitude and English. Job Seekers can also apply for jobs on LearningPundits. You can read more about Tips on cracking Aptitude Questions on Races and Games.