1 / 10

4-2 Components of Vectors

4-2 Components of Vectors. Choosing a Coordinate System. No correct answer on how to choose Choosing a Correct coordinate system will better allow certain problems to be solved Similar to laying a grid down on a sheet of paper Choose the center of the grid (origin)

aileen
Télécharger la présentation

4-2 Components of Vectors

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. 4-2 Components of Vectors

  2. Choosing a Coordinate System • No correct answer on how to choose • Choosing a Correct coordinate system will better allow certain problems to be solved • Similar to laying a grid down on a sheet of paper • Choose the center of the grid (origin) • On Earth: generally us the four Directions • Through air: x-axis chosen to be horizontal and y-axis chosen to be vertical • Direction of a vector is defined as the angle made with the x-axis measured counterclockwise

  3. Components • A vector may be broken up into two component vectors. • Parallel with x-axis (Ax) • Parallel with y-axis (Ay) • Original Vector A is the sum of the two component vectors • A = Ax + Ay • Vector Resolution is the process of breaking a vector into it’s components

  4. Components • All algebraic calculations involve only the components of vectors, not the vector itself • Find by using Trigonometry • Components are calculated where angle θ is measured counterclockwise from positive x-axis • Ax = A cosθ; cosθ = (adjacent side/hypotenuse) = Ax / A • Ay = A sin θ; sin θ = (opposite side/hypotenuse) = Ay / A

  5. Practice • A bus travels 23.0 km on a straight road that is 30o N of E. Where are the east and north components of its displacement? • Sketch problem • Known: A = 23.0 km = 30o • Unknown: Ax = ? Ay = ? • Calculation • Ax = A cosθ; Ax = (23.0 km)cos 30o • = +19.0 km • Ay = A sinθ; Ay = (23.0 km)sin 30o • = +11.5 km

  6. Practice • What are the components of a vector of a magnitude 1.5 m at an angle of 35o form the positive x-axis?

  7. Algebraic Addition of Vectors • Two or more vectors (A, B, C,…) may be added by first resolving each vector to its x & y components • The x-components are added to form the resultant (Rx) • Rx = Ax + Bx + Cx + … • The y-components are added to form the resultant (Ry) • Ry = Ay + By + Cy + … • To find the angle or direction of the resultant, the tangent of the angle that the vector makes with the x-axis is the following (tan θ = Ry/Rx) • Find the angle by using the tan-1 key

  8. Algebraic Addition of Vectors Cy By Ay C R Ry B A AxBxCx Rx

  9. Practice • A GPS reciever told you that your home was 15.0 km at a direction 40o North of West, but the only path led directly north. If you took that path and walked 10.0 km, how far, and in what direction would you have to walk to reach your home? • Draw the resultant vector, R from your original location to home • Draw A, the known displacement • Draw B, the unknown displacement

  10. A GPS reciever told you that your home was 15.0 km at a direction 40o North of West, but the only path led directly north. If you took that path and walked 10.0 km, how far, and in what direction would you have to walk to reach your home? • Rx = R cosθ ; (15.0 km) cos θ 140o; = -11.5 km • Ry= R sin θ ; (15.0 km) cos θ 140o; = +9.6 km • Ax = 0.0 km; Ay = 10.0 km • R = A + B; so B = R – A • Bx = Rx – Ax = (-11.5 km) – (0.0 km) = -11.5 km • By = Ry – Ay = (9.6 km) – (10.0 km) = -0.4 km • B = √Bx2 + By2 = √(-11.5 km)2 + (-0.4 km)2 • = 11.5 km • tan θ = By/Bx = (-0.4 km)/(-11.5 km) = +0.035 • θ = tan-1(+0.035) = 2.0o • B = 11.5 km, 2.0o south of west

More Related