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Feedback theorem derivation

Feedback theorem derivation. i y. i x. v e. v out. v i. i z. 1. i z = 0. i y. i x. v e. v out. v i. i z. 2. v i = 0. i y. i x. v e. v out. v i. i z. 3. superposition. i y. i x. v e. v out. v i. i z. 3(i) null double injection i x -> 0. i y. i x. v e. v out.

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Feedback theorem derivation

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  1. Feedback theorem derivation iy ix ve vout vi iz

  2. 1. iz = 0 iy ix ve vout vi iz

  3. 2. vi = 0 iy ix ve vout vi iz

  4. 3. superposition iy ix ve vout vi iz

  5. 3(i) null double injection ix-> 0 iy ix ve vout vi iz

  6. 3(ii) null double injection iy-> 0 iy ix ve vout vi iz

  7. 3(iii) null double injection vout-> 0 iy ix ve vout vi iz

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