1 / 12

Today’s Agenda

Today’s Agenda. Programming Exercise. Histogram. int main() { int freq[20],marks[50]; int i,j,n,m; n = 20; m = 10;//no. of students for(i=0;i&lt;n;i++) //invariant freq[0..i-1] = 0 freq[i] = 0; //pre-condn: each 0&gt;= marks[i]&lt;=20 for(i=0;i&lt;m;i++) scanf(&quot;%d<br>&quot;,&amp;marks[i]);

Télécharger la présentation

Today’s Agenda

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Today’s Agenda Programming Exercise

  2. Histogram

  3. int main() { int freq[20],marks[50]; int i,j,n,m; n = 20; m = 10;//no. of students for(i=0;i<n;i++) //invariant freq[0..i-1] = 0 freq[i] = 0; //pre-condn: each 0>= marks[i]<=20 for(i=0;i<m;i++) scanf("%d\n",&marks[i]); i=0; while(i<m) //pre-condn: freq[i] = 0; { freq[marks[i]]++; // loop invariant m <= freq[marks[i]] >= 0 i++; } printf("frequency distribution\n"); for(i=0;i<n;i++) printf("%d\n",freq[i]); }

  4. Remove Duplicates

  5. int removeDuplicate(int a[],int size) { int i,j,flag=0,k,count,c=0; for(i=1;i<size;i++)// loop invariance is all elements between a[0..i-1] should be unique or duplicates should be less than 3 { if(a[i] == a[i-1]) { if(!flag) { j = i; flag = 1; printf("j = %d and flag = %d\n",j,flag); } } else if(flag && c > 3)// checking if the # of duplicates > 3 { printf("i=%d\n",i); count = i-j; printf("count = %d\n",count); while(count>0)//loop invariant here is 'count' number of duplicates are remaining between i to j { for(k=j;k<size-1;k++) a[k] = a[k+1]; size--; count--; } flag = 0; } c++;//increamenting the count of duplicates } return size; }

  6. Set Operations

  7. SetDef.h(Data Definitions File) #define MAX 20 typedef int set[MAX]; typedef int size; typedef enum{TRUE,FALSE}boolean;

  8. SetOps.h #include"SetDef.h" extern void readSet(set S,size n); extern boolean isMember(set S,int x,size n); extern size setUnion(set s1,set s2,set s3,size n1,size n2);

  9. main.c #include<stdio.h> #include"SetOps.h" int main() { set s1 ;//= {1,3,5,7,9}; set s2 ;//= {2,3,5}; set s3; int i; boolean flag; size n1,n2,n3; n1 = 5; n2 = 3; int x = 7; readSet(s1,n1); readSet(s2,n2); flag = isMember(s1,x,n1); if(flag == TRUE) printf("%d is member of s1\n",x); else printf("%d is not member of s1\n",x); n3 = setUnion(s1,s2,s3,n1,n2); for(i=0;i<n3;i++) printf("%d ",s3[i]); printf("\n"); }

  10. SetOps.c #include"SetDef.h" #include<stdio.h> void readSet(set S,size n) { int i; for(i=0;i<n;i++) scanf("%d ",&S[i]); }

  11. boolean isMember(set S,int x,size n) { int i; for(i=0;i<n;i++) { if(S[i] == x) return TRUE; else if(S[i] > x) return FALSE; } return FALSE; }

  12. size setUnion(set s1,set s2,set s3,size n1,size n2) { int i,j,k,l; k=0;i=0;j=0; while((i<n1)&&(j<n2)) { if(s1[i]==s2[j]) { s3[k] = s1[i]; i++; j++; k++; } else if(s1[i]<s2[j]) { s3[k] = s1[i]; k++; i++; } else { s3[k] = s2[j]; k++; j++; } } if(i < n1) for(l=i;l<n1;l++) { s3[k] = s1[l]; k++; } else if(j<n2) for(l=j;l<n2;l++) { s3[k] = s2[l]; k++; } return k; }

More Related