1 / 28

Momentum & Impulse

Momentum & Impulse. Momentum (p). “inertia of motion” p = mv Units for momentum  Kg*m/s Vector Quantity One way of looking at it…How much an object in motion… wants to stay in motion Lot of momentum  hard to stop. How can you change an object’s momentum??.

alka
Télécharger la présentation

Momentum & Impulse

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Momentum & Impulse

  2. Momentum (p) • “inertia of motion” • p = mv • Units for momentum  Kg*m/s • Vector Quantity • One way of looking at it…How much an object in motion… wants to stay in motion • Lot of momentum  hard to stop

  3. How can you change an object’s momentum?? • Newton’s 2nd Law states a net force causes an acc. • An acc. Changes the velocity • Changing the velocity, changes the momentum

  4. Impulse Momentum Theorem • Applying a force over a time interval changes the momentum • F changes v, therefore (mv) changes • Never looked at a relationship between ‘F’ and ‘t’ • F x t = Impulse • Since an impulse changes ‘v’, this changes momentum • Ft = Δ(mv)  Impulse-Momentum Theorem

  5. Newton’s 2nd Law reworked… • F = ma and a = (Δv/t) • F= m(Δv/t) then multiply both sides by ‘t’ • Ft = mΔv which is the same thing as • Ft = Δmv • Impulse- Momentum Theorem is just Newton’s 2nd Law written a different way

  6. Examples • Boxing gloves vs. MMA gloves • http://www.yourdiscovery.com/video/future-cars-nido/ • Features on a car?? • Pillow punch vs. brick punch • Bungee jump w/ elastic cord vs. rigid cord • Egg toss competition • “rolling with a punch”

  7. Bouncing? • Greater Δ(mv) than just stopping an object?? • Why??  ….greater Δv • Going from -5 m/s to 5 m/s is a greater velocity change than going from -5 m/s to 0 m/s, therefore greater Δmv and impulse

  8. Pelton Wheel Example • Paddles are cups instead of just flat planks • Allows water to change directions • Greater Δmv of water which means more impulse and wheel is turned much more effectively

  9. Example Problem

  10. Other Examples • Karate chop • http://www.youtube.com/watch?v=pLtPUgRueTE • http://www.youtube.com/watch?v=BblbLjwZC58&feature=related • http://www.youtube.com/watch?v=lupXlg4KaRg • http://www.youtube.com/watch?v=pTmRUH0uYgw • Mr. Schober gets assaulted by strangers… Story

  11. Conservation of Momentum • If no outside force is applied, then the total amount of momentum in a closed system will remain constant. • Only external forces can change momentum. • Σpi= Σpf • m1v1i +m2v2i …= m1v1f + m2v2f…

  12. Conservation of Momentum pai = m(v) pbi = m(0) pbf = m(v) paf = m(0)

  13. Conservation of Momentum • Momentum is conserved for all objects in the interaction, even if one doesn't stop pai + pbi = paf + pbf

  14. Is momentum conserved here? Yes, due to the vector nature of momentum.

  15. Is momentum conserved? A B • Initial velocities of both objects is 0. • pai = ma(0) • pbi = mb(0) • Σpi = 0

  16. Is momentum conserved? A B • paf = ma(-va) • pbf = mb(vb) • pf = 0 • Σpi = Σpf, so momentum is conserved!! pf = ma(-va) + mb(vb)

  17. Why do internal forces result in momentum being conserved? • When Girl A pushes on Girl B, according to Newton’s 3rd Law, Girl B pushes on Girl A • How much? • These forces are equal in magnitude and opposite in direction • The time over which these forces act is exactly the same • Only while the girls are in contact, in this case

  18. How does a gun work?

  19. How does the gun work? • Only forces are internal (no net external forces are adding impulse to the system) • The momentum of both will add up to zero (bullet is +, gun is -)

  20. Why do internal forces result in momentum being conserved? • Impulse is equal in magnitude but opposite in direction • I = (ΣF)(Δt) • Forces are equal and opposite, times are equal • Δp is equal in magnitude, opposite in direction, resulting in Σp = 0!!

  21. Collisions http://www.flixxy.com/golf-ball-slow-motion.htm - Golf Ball during a surprising inelastic collision http://www.youtube.com/watch?v=pQ9NiazPYI8 --- baseball • Inelastic • Any collision in which momentum is conserved but kinetic energy is not • Most ‘real’ collisions are of this kind • KE is not conserved because some is lost to the deformation • m1v1i+ m2v2i= m1v1f + m2v2f • Perfectly Inelastic • Objects collide and stick together • KE not conserved • m1v1i + m2v2i = (m1 + m2) vf • Elastic • Both momentum and KE are conserved • “perfectly “elastic collisions only occur in real life at the subatomic level, but will treat any collision labeled as “elastic” as being ‘perfectly’ elastic • Collisions between billiard balls or between air molecules and the surface of a container are both highly elastic • No Energy lost to deformation • m1v1i+ m2v2i= m1v1f + m2v2f And • ½m1v1i2 + ½m2v2i2 = ½m1v1f2 + ½m2v2f2 • When combining these two and reducing we get…. V1i – v2i =-(v1f – v2f)

  22. Example problem

  23. Problem Solving #1 • A 6 kg fish swimming at 1 m/sec swallows a 2 kg fish that is at rest. Find the velocity of the fish immediately after “lunch”. • System is both fish, and collision is perfectly inelastic so ….. • Σpi= Σpf • (m1v1i)+ (m2v2i)= (m 1+ m2)vf • 6(1) + (2)(0) = (6+2) vf • Vf =6/8 = .75 m/s

  24. Problem Solving #2 • Now the 6 kg fish swimming at 1 m/sec swallows a 2 kg fish that is swimming towards it at 2 m/sec. Find the velocity of the fish immediately after “lunch”. • System is both fish, so…. • Σpi = Σpf • (Σ(mv))i= (Σ(mv))f • (m1v1i)+ (m2v2i)= (m 1+ m2)vf • (6 kg)(-1 m/s) + (2 kg)(2 m/s) = (6 kg + 2 kg)(vf) • -6 kg.m/s + 4 kg.m/s = (8 kg)(vf) • vf=-2 kg.m/s / 8 kg vf= -.25 m/s

  25. Collisions in 2-D (more to be posted later) • Σpxi = Σpxf • Σpyi = Σpyf Momentum is a vector, so momentum must be conserved in the x-direction, and in the y-direction

  26. Inelastic in 2-D ?? 1 kg ?? .5 kg 2.2 m/s 33° 1.5 m/s

  27. Perfectly Inelastic in 2-D 1.5 kg 1 kg 2.5 m/s 1.3 m/s .5 kg

More Related