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ME451 Kinematics and Dynamics of Machine Systems

ME451 Kinematics and Dynamics of Machine Systems. Composite Joints – 3.3 Gears and Cam Followers – 3.4 February 17, 2009. © Dan Negrut, 2009 ME451, UW-Madison. Before we get started…. Last Time We looked at several relative constraints Revolute Joint Translational Joint

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ME451 Kinematics and Dynamics of Machine Systems

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  1. ME451 Kinematics and Dynamics of Machine Systems Composite Joints – 3.3 Gears and Cam Followers – 3.4 February 17, 2009 © Dan Negrut, 2009ME451, UW-Madison

  2. Before we get started… • Last Time • We looked at several relative constraints • Revolute Joint • Translational Joint • Distance Constraint • x, y,  relative constraints • Discussed the concept of joint (constraint) attributes • Recall the drill that you have to go through in relation to each joint to provide what it takes to carry out Kinematics Analysis • Five step procedure: • Identify and analyze the physical joint • Derive the constraint equations associated with the joint • Compute constraint Jacobian q • Get  (RHS of velocity equation) • Get  (RHS of acceleration equation, this is challenging in some cases) • Today • Covering composite joints, cam follower type joints, and gears 2

  3. Example 3.3.4 • Consider the slider-crank below. Come up with the set of kinematic constraint equations to kinematically model this mechanism 3

  4. Composite Joints (CJ) • Revolute-Revolute CJ • Also called a coupler • Practically eliminates need of connecting rod • Given to you (joint attributes): • Location of points Pi and Pj • Distance dij of the massless rod • Revolute-Translational CJ • Given to you (joint attributes): • Distance c • Point Pj (location of revolute joint) • Axis of translation vi’ • Just a means to eliminate one intermediate body whose kinematics you are not interested in 4

  5. Composite Joints • One follows exactly the same steps as for any joint: • Step 1: Physically, what type of motion does the joint allow? • Step 2: Constraint Equations (q,t) = ? • Step 3: Constraint Jacobian q = ? • Step 4:  = ? • Step 5:  = ? 5

  6. Moving on to gears (section 3.4) 6

  7. Gears • Convex-convex gears • Gear teeth on the periphery of the gears cause the pitch circles shown to roll relative to each other, without slip • First Goal: find the angle  , that is, the angle of the carrier • What’s known: • Angles i and j • The radii Ri and Rj • You need to express  as a function of these four quantities plus the orientation angles i and j • Kinematically: PiPj should always be perpendicular to the contact plane 7

  8. Gears - Discussion of Figure 3.4.2 (Geometry of gear set) 8

  9. Gears - Discussion of Figure 3.4.2 (Geometry of gear set) Note: there are a couple of mistakes in the book, see Errata slide before 9

  10. Example: 3.4.1 • Gear 1 is fixed to ground • Given to you: 1 = 0 , 1 = /6, 2=7/6 , R1 = 1, R2 = 2 • Find 2 as gear 2 falls to the position shown (carrier line P1P2 becomes vertical) 10

  11. Gears (Convex-Concave) • Convex-concave gears – we are not going to look into this class of gears • The approach is the same, that is, expressing the angle  that allows on to find the angle of the • Next, a perpendicularity condition using u and PiPj is imposed (just like for convex-convex gears) 11

  12. Example: 3.4.1 • Gear 1 is fixed to ground • Given to you: 1 = 0 , 1 = /6, 2=7/6 , R1 = 1, R2 = 2 • Find 2 as gear 2 falls to the position shown (carrier line P1P2 becomes vertical) 12

  13. Rack and Pinion Preamble • Framework: • Two points Pi and Qi on body i define the rack center line • Radius of pitch circle for pinion is Rj • There is no relative sliding between pitch circle and rack center line • Qi and Qj are the points where the rack and pinion were in contact at time t=0 • NOTE: • A rack-and-pinion type kinematic constraint is a limit case of a pair of convex-convex gears • Take the radius Ri to infinity, and the pitch line for gear i will become the rack center line 13

  14. Rack and Pinion Kinematics • Kinematic constraints that define the relative motion: • At any time, the distance between the point Pj and the contact point D should stay constant (this is equal to the radius of the gear Rj) • The length of the segment QiD and the length of the arc QjD should be equal (no slip condition) • Rack-and-pinion removes two DOFs of the relative motion between these two bodies 14

  15. Rack and Pinion Pair • Step 1: Understand the physical element • Step 2: Constraint Equations (q,t) = ? • Step 3: Constraint Jacobian q = ? • Step 4:  = ? • Step 5:  = ? 15

  16. End Gear KinematicsBegin Cam-Follower Kinematics 16

  17. Preamble: Boundary of a Convex Body • Assumption: the bodies we are dealing with are convex • To any point on the boundary corresponds one value of the angle  (this is like the yaw angle, see figure below) • The distance from the reference point Q to any point P on the convex boundary is a function of : • It all boils down to expressing two quantities as functions of  • The position of P, denoted by rP • The tangent at point P, denoted by g 17

  18. Cam-Follower Pair • Assumption: no chattering takes place • The basic idea: two bodies are in contact, and at the contact point the two bodies share: • The contact point • The tangent to the boundaries • Recall that a point is located by the angle i on body i, and j on body j. • Therefore, when dealing with a cam-follower, in addition to the x,y, coordinates for each body one needs to rely on one additional generalized coordinate, namely the contact point angle : • Body i: xi, yi, fi, i • Body j: xj, yj, fj, j 18

  19. Cam-Follower Constraint • Step 1: Understand the physical element • Step 2: Constraint Equations (q,t) = ? • Step 3: Constraint Jacobian q = ? • Step 4:  = ? • Step 5:  = ? 19

  20. Example • Determine the expression of the tangents g1 and g2 20

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