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Section 4 Conservation of Energy

Section 4 Conservation of Energy. I. Energy Transformations. At the top of the hill, PE is at it’s maximum. What about KE?. KE = 0.0 J. PE = mgh PE = (515 kg)(9.8 m/s 2 )(70.0 m). PE = 353,290 J. I. Energy Transformations. At the bottom of the hill, KE is at it’s maximum.

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Section 4 Conservation of Energy

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  1. Section 4 Conservation of Energy

  2. I. Energy Transformations At the top of the hill, PE is at it’s maximum. What about KE? KE = 0.0 J PE = mgh PE = (515 kg)(9.8 m/s2)(70.0 m) PE = 353,290 J

  3. I. Energy Transformations At the bottom of the hill, KE is at it’s maximum. What about PE? PE = 0.0 J KE = ½mv2 KE = ½(515 kg)(37.1)2 All of the PE was converted to KE. KE = 353,290 J

  4. As the car reaches the top of the 2nd hill, KE = PE. KE = ½mv2 KE = ½(515 kg)(26.2)2 PE = mgh PE = (515 kg)(9.8 m/s2)(35.0 m) KE = 176,758 J PE = 176,645 J

  5. II. The Law of Conservation of Energy Energy cannot be created or destroyed. 1. Energy changes from one form to another Roller coasters lose energy through: Sound Friction Air Resistance

  6. III. Efficiency of Machines Not all work done by a machine is useful 1. Work Input is not equal to Work Output Energy is lost through: Sound Friction Air Resistance

  7. Example: With this pulley system, we should be able to lift 100 pounds with only 25 pounds of force. However, friction and heat would cause some of the input force (25 lbs.) to be lost.

  8. B. Efficiency Equation

  9. Sample problems pg. 407 Questions 1 – 3

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