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高等電機機械報告

高等電機機械報告. 學生：江銘棟 學號： 4992c082.

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高等電機機械報告

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  1. 高等電機機械報告 學生：江銘棟 學號：4992c082

  2. 9.5 A 500-W, four-pole, 115-V, 60-Hz single-phase induction motor has the following parameters (resistances and reactances in Ω/phase ):Core loss=38W Friction and windage=11.8WFind the speed, stator current, torque, power output, and efficiency when the motor is operating at rated voltage and a slip of 4.2 percent 翻譯：一個500瓦，四極，115伏特，60赫茲，單相非同步電動機的參數如下： R1=1.68 R2=2.96 X1=1.87 Xm=60.6 X2=1.72 磁芯損失 =38W 摩擦和風阻=11.8W 找出轉速，定子電流，轉矩，輸出功率，效率，當電動機運作在額定電壓下的效率為4.2％的時候

  3. 找出轉速，定子電流，轉矩，輸出功率，效率，當電動機運作在額定電壓下的效率為4.2％的時候找出轉速，定子電流，轉矩，輸出功率，效率，當電動機運作在額定電壓下的效率為4.2％的時候 Solve: 總阻抗 z=26.25∠49 定子電流 Imain=v/z=115/26.25=4.38 功率因數 Power factor=cos(49)=0.65 輸出功率 Pout=205 轉速 Speed=1724r/min 轉矩 Torque=1.13N.m 效率 Efficiency=Pout/Pin=63%

  4. 9.7At standstill the rms currents in the main and auxiliary windings of a four –pole capacitor – start induction motor are Imain = 20.7 A and Iaux 11.1 A respectively .the auxiliary – winding current leads the main – winding current by 53 . the effective turns per pole ( i.e., the number of turns corrected for the effects of winding distribution ) are Nmain = 42 and Naux = 68 . the winding are in space quadrature .A. determine the peak amplitudes of the forward and backward stator-mmf waves.B. Suppose it were possible to adjust the magnitude and phase of there auxiliary-winding current . what magnitude and phase would produce a purely forward mmf wave ? 翻譯：在靜止狀態中四極電容的主要和輔助繞組中的電流有效值 - 起動非同步步電動機的IMAIN=20.7 和IAUX11.1 輔助繞組電流超前於主繞組53的電流。每一極的有效圈數（即，對於繞組分佈的影響，校正線圈匝數）是Nmain= 42和NAUX=68。繞組在空間正交。 A.確定前向和後向定子磁動勢波的峰值振幅。 B.假定這是可能的調整有輔助繞組電流的幅值和相位。什麼幅度和相位會產生一個純粹的前鋒MMF波？

  5. Solve： A. 從第四章的4.6式得知磁勢波公式為 經由題目所給的Imain=20.7A Nmain=42代入4.6式 Iaux=11.1A Naux=68代入4.6式 求出反向磁勢=340A.turns B. 當輔助電流Iaux的電流大小及相位未改變所以在 Imain.Nmain.Naux固定下經由繞組及電流比例公式換算過後

  6. 9.9 The equivalent-circuit parameters of an 8-KW, 230-V, 60-Hz, four-pole, two-phase,squirrel-cage induction motor in ohm per phase are • This motor is operated from an unbalance two-phase, 60-Hz, source whose phase voltages are, respectively, 223 and 190 V, the smaller voltage leading the larger by 73°. For a slip of 0.045, find • a. the phase current in each of the winding and • b. the internal machine power.

  7. 翻譯：一個鼠籠式感應電動機的參數為8千瓦，230伏特，60赫茲，4極，兩相翻譯：一個鼠籠式感應電動機的參數為8千瓦，230伏特，60赫茲，4極，兩相 該電動機是操作在不平衡的兩項，60赫茲，其相電壓分別為223和190伏特時，較小的電壓超前較大電壓73度 A. 找出每項的相電流 B. 找出內部功率

  8. Ans: (a)

  9. b.

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