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ACT Problem

ACT Problem. (6a – 12) – (4a + 4) = ? 2(a+2) 2(a+4) 2(a-2) 2(a-4) 2(a-8). ACT Problem. (6a – 12) – (4a + 4) = ? Suppose a = 1. (6(1)-12) – (4(1) + 4) (6-12) – (4+4) -6 – 8 -14. ACT Problem. (6a – 12) – (4a + 4) = ? Our answer was a -14 If a = 1, then 2(a+2) = 2(3) = 6

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ACT Problem

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  1. ACT Problem (6a – 12) – (4a + 4) = ? • 2(a+2) • 2(a+4) • 2(a-2) • 2(a-4) • 2(a-8)

  2. ACT Problem (6a – 12) – (4a + 4) = ? Suppose a = 1. (6(1)-12) – (4(1) + 4) (6-12) – (4+4) -6 – 8 -14

  3. ACT Problem (6a – 12) – (4a + 4) = ? Our answer was a -14 If a = 1, then • 2(a+2) = 2(3) = 6 • 2(a+4) = 2(5) = 10 • 2(a-2) = 2(-1) = -2 • 2(a-4) = 2(-3) = -6 • 2(a-8) = 2(-7) = -14

  4. Vertical Angles and Transversals

  5. Naming an Angle 4 Ways By the points that Compose it: <NMO or <OMN By the vertex (or pivot point of the angle): <M Or the number associated with it: <1

  6. Vertical Lines Vertical lines are opposite each other. They are always equal.

  7. Transversal of Parallel Lines Angles 1=3=5=7 Angles 2=4=6=8

  8. Angles Formed by a Transversal Alternate exterior Alternate interior

  9. Angles Formed by a Transversal Corresponding Consecutive Interior

  10. Solving for x Set up the information you know and solve for x as you would in algebra: 2x + 4 + 38 = 90 2x + 42 = 90 -42 -42 2x = 48 2 2 x = 24 2x + 4

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