1 / 9

Al13 EO3 TSW6 Linear Eq.

Al13 EO3 TSW6 Linear Eq. Ye Rin. Shelby. TSW 6. Linear Equation, Solving!!. Using a Table as a Check. Long. 400 students take Spanish and has been increasing 20 students per year. 98 students take German and has been decreasing 5 students per year.

conan-sparks
Télécharger la présentation

Al13 EO3 TSW6 Linear Eq.

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Al13 EO3 TSW6 Linear Eq. Ye Rin Shelby TSW 6.LinearEquation, Solving!!

  2. Using a Table as a Check. Long • 400 students take Spanish and has been increasing 20 students per year. • 98 students take German and has been decreasing 5 students per year. • When will there be five times as many students taking Spanish as taking German? Making it Shorter

  3. verbal + label taking Spanish (400) + Increase (20) x Years (x) = Number taking German (98) Decrease (5) Years (x) 5 ( - x ) Algebraic 400+20x=5(98-5x) 400+20x=490-25x 400+20x+25x=490-25x+25x 400+45x=490 400-400+45x490-400 45x=90 X=2 Students taking Spanish will be five times than students taking German in two years!!

  4. Check Table 400+20=420 equal 98*5=490

  5. Using a Graph as a Check • A gazelle can run 73 ft per sec. For several minutes • A cheetah can run faster(88 ft per sec.) but can only sustain its top speed for about 20 sec. • How Far away from the cheetah does the gazelle need to stay for it to be safe?

  6. Solution Use a diagram. • If the gazelle is to far away for the cheetah to catch it within 20 seconds, the gazelle is probably safe. X Gazelle caught in 20 seconds If the gazelle is closer to the cheetah than x feet, the cheetah can catch the gazelle If the gazelle is farther away than x feet, the gazelle is in the safety zone

  7. … • To find the “Safety zone,” first find the starting distance for which the cheetah reaches the gazelle in 20 seconds. • To find the distance each animal runs in 20 seconds use the formula d=rt Distance Gazelle runs in 20 sec. Gazelle’s starting distance from cheetah Distance cheetah runs in 2o seconds Verbal Model + = Gazelle’s distance = 73 x 2o (feet) Gazelle’s starting distance from cheetah = x (feet) Cheetah’s distance = 88 x 20 (feet) 73 x 20 + x = 88 x 20 Labels Algebraic Model

  8. … • You find that x= 300, so the gazelle needs to stay more than 300 ft away from the cheetah to be safe. • Check~ Use a table or graph to check your answer. Why? • A graph helps you see relationships How? • First, make a table • Then, plot the points • Next, find and mark the points for every 5 sec.

  9. Thank you for watching!

More Related