1 / 13

Right Triangle Trig Review

Right Triangle Trig Review. Given the right triangle from the origin to the point (x, y) with the angle , we can find the following trig functions:. Replacing (x, y) with these new values, we get the point as:. Moving to the circle centered at the origin.

damara
Télécharger la présentation

Right Triangle Trig Review

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Right Triangle Trig Review Given the right triangle from the origin to the point (x, y) with the angle , we can find the following trig functions:

  2. Replacing (x, y) with these new values, we get the point as: Moving to the circle centered at the origin

  3. Moving to the circle centered at the origin with radius “r”, we find two points A and B.

  4. We can use the distance formula to find the distance AB.

  5. Next, construct the angle in a circle with the same radius r. Using the SAS property, the triangle AOB in the previous example is congruent to the triangle COD in this example. Therefore, the length of segment AB must equal the length of segment CD. It must also be true that

  6. Finding points C and D and the length CD, we get:

  7. By similar triangles, we know the length of AB = length of CD. We can square both sides to get rid of the square roots.

  8. Simplifying by squaring each group, we get: Every term has an r2. Divide each term by r2. Using the pythagorean identity, we know

  9. Simplifying, we get: Subtracting the 2’s from each side, we get: Each term has a -2, so divide out the -2.

  10. However, recall that Replacing in the equation, we get:

  11. To find a rule for , we replace v with –v. Simplifying with odd/even rules, we get:

  12. To get the sum/difference rules for sin, we will use the co-function rule. Let’s use the cosine rule to find Using the cosine sum rule Using the co-function rules, we get:

  13. Therefore: To get the sin(u+v) rule, Using the odd/even functions, we get:

More Related