1 / 11

Hardy-Weinberg Problems

Hardy-Weinberg Problems. 2450=bald=q 2 2550 =hairy=p 2 +2pq 5000=total. q=.7 p=1-.7=.3. q 2 = 2450 =.49 5000. . . p 2 + 2pq + q 2 = 1 .592+2(.59x.41)+.412=1 .35 + .48 + .17 = 1. p 2 + 2pq + q 2 = 1 32 + 2(.3x.7)+.72=1 .09 + .42 + .49 = 1

daphne
Télécharger la présentation

Hardy-Weinberg Problems

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Hardy-Weinberg Problems 2450=bald=q2 2550=hairy=p2+2pq 5000=total q=.7 p=1-.7=.3 q2 =2450 =.49 5000 . p2 + 2pq + q2 = 1 .592+2(.59x.41)+.412=1 .35 + .48 + .17 = 1 p2 + 2pq + q2 = 1 32 + 2(.3x.7)+.72=1 .09 + .42 + .49 = 1 9 + 42 + 49 = 100 X 18 H’s 42 h’s 42 H’s60 H’s 60 H’s 102 total genes 42 = .41=q 60 =.59=p 102 102

  2. Hardy-Weinberg Problems #4 6400=smooth tongued=q2 3600=forked tongued=p2+2pq 10,000 6400=q2=.64 10,000 1-q=p 1-.8=.2 q2=.64 q=.8 p2 + 2pq + q2 = 1 .22+2(.2 X .8) + .82=1 .04 + .32 + .64= 1 FF Ff ff 4 + 32 + 64 = 1 p2 + 2pq + q2 = 1 .562+2(.56X.44)+.442=1 .31 + .49 + .19 = 1 X 8 F’s 32 f’s 32 F’s 40 F’s 40 F’s 72 genes 40=.56=p 32=.44=q 72 72 a. freq.of F=.2 freq. of f =.8 b. .32 Ff c. freq.of F=.56 freq. of f =.44 d. FF=.31 Ff =.49 ff =.19

  3. Hardy-Weinberg Problems #5 3120=.65=q2 4800 q2=.65 q=.81 3120=brown eyed=q2 1680=black eyed=p2+2pq 4800 p=1-.81 p=.19 p2 + 2pq + q2 = 1 .192+2(.19 x .81)+.812=1 .04 + .31 + .65 =1 BB Bb bb

  4. Hardy-Weinberg Problems #6 4860=q2=.81 6000 4860=white=q2 1140=green=p2+2pq 6000 p=1-.9 p=.1 q2=.81 q=.9 p2 + 2pq + q2 = 1 .12+2(.1 x .9)+ .92=1 .01 + .18 + .81 =1 GG Gg gg 1 18 81 =100 p2 + 2pq + q2 = 1 .532 +2(.53 X .47)+.472=1 .28 + .50 + .22 = 1 GG Gg gg .78 green x 2G’s 18g’s 18G’s 20G’s 20G’s 38genes 20=.53=p 18=.47=q 38 38

  5. Hardy-Weinberg Problems #7 1600 weak-legged=q2 8400 strong-legged=p2 +2pq 10,000 1600=q2=.16 10,000 q2=.16 q=.4 p2 + 2pq + q2 = 1 .62+2(.6 X .4)+.42=1 .36 + .48 + .16 = 1 AA Aa aa p=1-.4 p=.6 a. .4 b. .6 c. .36 d. .48

  6. Hardy-Weinberg Problems #8 180=q2=.36 500 180=nude=q2 320=hairy=p2+2pq 500 p=1-.6 p=.4 q2=.36 q=.6 p2 + 2pq + q2 = 1 .42+2(.4 x .6)+ .62=1 .16 + .48 + .36 =1 HH Hh hh 16x.5 48x.5 36 =100 8 24 36 p2 + 2pq + q2 = 1 .292 +2(.29 X .71)+.712=1 .08 + .41 + .50 = 1 HH Hh hh .49 hairy 16H’s 24h’s 40H’s 24H’s72h’s96h’s 40H’s 96h’s 136genes a. .4 e. .49 b. .48 c. .16 d. .71 40=.29=p 96=.71=q 136 136

  7. Hardy-Weinberg Problems #9 2400=q2=.16 15000 2400=normal=q2 12600=clumsy=p2+2pq 15000 p=1-.4 p=.6 q2=.16 q=.4 p2 + 2pq + q2 = 1 .62+2(.6 x .4)+ .42=1 .36 + .48 + .16 =1 RR Rr rr 36X.25 48X.25 16 9 12 16 p2 + 2pq + q2 = 1 .412 +2(.41 X .59)+.592=1 .17 + .48 + .35 = 1 GG Gg gg .65 clumsy 18R’s 12r’s 30R’s 12R’s 32r’s 44r’s 30R’s 44r’s 74genes a. .6 e. .48 i. .35 b. .4 f. .59 c. .36 g. .41 d. 16 h. .65 30=.41=p 44=.59=q 74 74

  8. Hardy-Weinberg Problems #10 720=q2=0.0144 50000 720=dark=q2 49280=light=p2+2pq 50000 p=1-.12 p=.88 q2=.0144 q=.12 p2 + 2pq + q2 = 1 .882+2(.88 x .12)+ .122=1 .774 + .21 + .0144 =1 RR Rr rr 774X.10 210X.10 14 77.4 21 14 p2 + 2pq + q2 = 1 .782 + 2(.78 x .22)+ .222=1 .61 + .34 + .04 =1 RR Rr rr 61X.10 34X.10 4 6 3.4 4 12L’s 3.4l’s 15.4L’s 3.4L’s 8 l’s 11.4 l’s 15.4L’s 11.4l’s 26.8genes 155L’s 21l’s 176L’s 21L’s 28l’s 49l’s 176L’s 49l’s 225genes 15.4=.57=p 11.4=.43=q 26.8 26.8 2nd generation 176=.78=p 49=.22=q 225 225 1st gen.

  9. Hardy-Weinberg Problems #10 cont. p2 + 2pq + q2 = 1 .572+2(.57 x .43)+ .432=1 .32 + .49 + .19 =1 RR Rr rr 32X.1 49X.1 19 3.2 4.9 19 p2 + 2pq + q2 = 1 .212 + 2(.21 x .79)+ .792=1 .04 + .33 + .62 =1 RR Rr rr 4X.1 33X.1 62 .4 3.3 62 .8 L’s 3.3 l’s 4.1 L’s 3.3 L’s 62.0 l’s 65.3 l’s 4.1 L’s 65.3 l’s 56 genes 6.4L’s 4.9 l’s 11.3 L’s 4.9L’s 38 l’s 42.9 l’s 11.3L’s 42.9l’s 54.1genes 4th generation 4.1=.06=p 25.3 =.94=q 69.9 69.4 3rd generation 11.3=.21=p 42.9=.79=q 54.1 54.1

  10. Hardy-Weinberg Problems #11 240=q2=0.04 6000 240=camou=q2 5760=solid=p2+2pq 6000 p=1-.2 p=.8 q2=.04 q=.2 p2 + 2pq + q2 = 1 .82 + 2(.8 x .2) + .22 =1 .64 + .32 + .04 = 1 RR Rr rr 64X.1 32X.1 4 6.4 3.2 4 p2 + 2pq + q2 = 1 (.59)2 + 2(.59 x .41)+ (.41)2=1 .34 + .48 + .17 =.99 RR Rr rr a. .8 e. .59 b. .2 f. .41 c. .32 g. .34 d. .64 h. .48 12.8L’s 3.2 l’s 16 L’s 3.2L’s 8 l’s 11.2 l’s 16 L’s 11.2 l’s 27.2 genes 16=.59=p 11.2=.41=q 27.2 27.2

  11. Hardy-Weinberg Problems #12 1200=total sample=p2+2pq+q2 - 27=sickle-cell=q2 1173=p2+2pq q2=.0225 q=.15 p=1- .15 p=.85 27=q2=0.0225 1200 p2 + 2pq + q2 = 1 .852 + 2(.85 x.15) + .152 =1 .7225 + .255 + .0225 = 1 AA Aa aa 722.5X.2 255 22.5 144.5 255 p2 + 2pq + q2 = 1 (.68)2 + 2(.68 x .32)+(.32)2=1 .46 + .44 + .10 =.99 AA Aa aa X a. .15 b. .85 c. .7225 d. .255 e. 68 f. .32 g. .46 h. .44 289A’s 255a’s 255A’s 544A’s 544A’s 799 genes 544=.68=p 255=.32=q 799 799

More Related