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Equations, Inequalities, and Applications

2. Equations, Inequalities, and Applications. 2.6 Ratio, Proportion, and Percent. Objectives. 1. Write ratios. 2. Solve proportions. 3. Solve applied problems using proportions. 4. Find percents and percentages. Writing Ratios. Ratio

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Equations, Inequalities, and Applications

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  1. 2 Equations, Inequalities, and Applications

  2. 2.6 Ratio, Proportion, and Percent Objectives 1. Write ratios. 2. Solve proportions. 3. Solve applied problems using proportions. 4. Find percents and percentages.

  3. Writing Ratios Ratio A ratio is a comparison of two quantities using a quotient. The ratio of the number a to the number b is written atob,a:b, or

  4. 4 7 7 yd 8 ft 8 ft 4 9 4 yd 6 yd 18 ft . = . = = Write Ratios Example 1Write a ratio for each word phrase. (a) The ratio of 7 yards to 4 yards is (b) To find the ratio of 8 feet to 6 yards, first convert 6 yards to feet. 6 yards = 6 • 3 = 18 ft The ratio of 8 feet to 6 yards is thus

  5. Write Ratios Example 2 What size is the best buy? That is, which size has the lowest unit price? PEANUT BUTTER

  6. $3.49 $4.99 $6.79 18 28 40 Write Ratios Example 2 (continued) = $0.194 = $0.178 Best Buy! = $0.170 Because the 40-oz size produces the lowest unit price, it is the best buy.

  7. a c a c = = b d b d If , then ad and bc are equal and are called cross products. A proportion says that two ratios are equal, so it is a special type of equation. We read the proportion Solve Proportions (b, d ≠ 0). as “a is to b as c is to d.” We can also find the products ad and bc by multiplying diagonally.

  8. Example 3 Solve the proportion. 2 x 2 x 3 3 51 51 = = Solve Proportions 2 • 51 = 3 • x Cross products must be equal. 102 = 3x Multiply. 34 = x Divide by 3. Check by substituting 34 for x in the proportion. The solution is 34.

  9. Example 4 Solve the equation. = w + 1 w + 1 w – 4 w – 4 6 3 6 3 = Solving Proportions 6 ( w – 4 ) = 3 ( w + 1 ) Cross products must be equal. 6w – 24 = 3w + 3 Distribute. 6w = 3w + 27 Add 24. 3w = 27 Subtract 3w. w = 9 Divide by 3. Check that the solution is 9.

  10. $35.04 $15.33 x 7.0 = Solve Applied Problems Using Proportions Example 5After Edwin pumped 7.0 gal of gasoline, the display showing the price read $15.33. When he finished pumping the gasoline, the display read $35.04. How many gallons did he pump? Price Price Gallons Gallons 15.33x = 7.0(35.04) Cross products must be equal. 15.33x = 245.28 Multiply. x = 16 Divide. He pumped a total of 16 gal. Check this answer. Notice that the way the proportion is set up uses the fact that the unit price is the same, no matter how the gallons are purchased.

  11. a P amount percent = = b 100 base 100 Find Percentages and Percents We can solve a percent problem by writing it as a proportion or . The amount, or percentage, is compared to the base (the whole amount). Since percent means per 100, we compare the numerical value of the percent to 100.

  12. a 16 a P = = 750 100 b 100 Find Percentages and Percents Example 6 What is 16% of 750. 100a = 750(16) Cross products must be equal. 100a = 12,000 Multiply. a = 120 Divide. Thus, 16% of 750 is 120.

  13. a 26 a P = = 15 100 b 100 Find Percentages and Percents Example 7 A CD with a regular price of $15 is on sale this week at 26% off. Find the amount of the discount and the sale price this week. 100a = 15(26) Cross products must be equal. 100a = 390 Multiply. a = 3.90 Divide. The amount of the discount on the CD is $3.90, and the sale price is $15.00 – $3.90 = $11.10.

  14. a P = b 100 255 P = 850 100 Find Percentages and Percents Example 7 A computer advertisement was listed in the newspaper for $595. The regular price was $850. What percent of the regular price was the savings? The savings amounted to $850 – $595 = $255. 100(255) = 850P Cross products must be equal. 25,500 = 850P Multiply. 30 = P Divide. The sale price represented a 30% savings.

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