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4 Practice Buoyancy Problems

CHAPTER 9. 4 Practice Buoyancy Problems. What is the mass of the block floating in water?. 10 cm 10 cm 25 cm. W block = F buoyant mg = Vg. Volume of block. m = (1000) ½(.25)(.10)(.10). m = 1.25 kg.

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4 Practice Buoyancy Problems

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  1. CHAPTER 9 4 Practice Buoyancy Problems

  2. What is the mass of the block floating in water? 10 cm 10 cm 25 cm Wblock = Fbuoyant mg = Vg Volume of block m = (1000)½(.25)(.10)(.10) m = 1.25 kg

  3. What is the mass of the cylinder floating in oil? r = 3 cm L = 12 cm Wcylinder = Fbuoyant mg = Vg Volume of cylinder m = (926)¾ (.12)(.03)2 m = .236 kg  = 926 kg/m3

  4. mcork Vcork cork = cork water 240 1000 What % of a solid cork ( = 240 ) will float below the surface of water? Wcork = Fbuoyant mg = Vg cork Vcork = (water)(x)Vcork = x = .24 = 24%

  5. x? 24 cm 30 cm mside Vside side = 5 cm m (.24)(.30)(.05) 2 MASSLESS SIDES & BOTTOM! The thick walls are made of Copper (  = 8930). How wide must the box be to float in water? Wbox = Fbuoyant mg = Vg (.30)(.24)x 64.3 = 1000 8930 = For ONE side x = .893 m m = 32.14 kg

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