1 / 34

What Does the Likelihood Principle Say About Statistical Process Control?

What Does the Likelihood Principle Say About Statistical Process Control?. Gemai Chen, University of Calgary Canada July 10, 2006. It is well know that given a random sample X 1 , X 2 , …, X n from , then is independent of and.

franz
Télécharger la présentation

What Does the Likelihood Principle Say About Statistical Process Control?

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. What Does the Likelihood Principle Say About Statistical Process Control? Gemai Chen, University of Calgary Canada July 10, 2006

  2. It is well know that given a random sample X1, X2, …, Xn from , then is independent of and

  3. Therefore, inference for  and  can be done using and separately.

  4. From a statistical theory point of view, this supports the practice that process mean and variability are usually monitored by two different control charts.

  5. For this presentation, let’s consider the widely used X-bar chart and the S chart.

  6. Now let X denote a certain quality characteristic of a process, let  denote the process mean and let  denote the process standard deviation.

  7. Suppose that Xij, i = 1, 2, … and j = 1, …, n, are measurements of X arranged in sub-groups of size n with i indexing the sub-group number.

  8. We assume that Xi1,…,Xinis a random sample from a normal distribution with mean  +a and standard deviation b, where a = 0 and b = 1 indicate that the process is in control.

  9. Define sample mean and sample variance by

  10. The 3-sigma X-bar chart plots the sample means against

  11. with a Type I Error probability 0.0027 when the process is in control.For the S chart, we use a version with probability control limits, where

  12. a probability 0.00135 is assigned to each tail so that the Type I Error probability is also 0.0027 when the process is in control.

  13. The joint behaviour of the (X-bar, S) combination judged by average run length (ARL) is summarized in the following table.

  14. ARL of (X-bar, S) CombinationWhen n = 5

  15. Some efforts have been made to use one chart by combining two existing charts, one for the mean and one for the variability.

  16. For example, the Max chart by Chen & Cheng plots

  17. where

  18. Under the same in control ARL of 185.4, the Max chart has the identical ARL performance to the (X-bar,S) combination.

  19. Can we design a control chart which by nature is meant to monitor both mean and variability simultaneously?

  20. Here we report what we have tried. First, asany test of uniformity can be turned into a chart.

  21. ARL Based on KolmogorovTest When n = 5

  22. ARL Based on Cramer-von Mises Test When n = 5

  23. ARL Based on Anderson-Darling Test When n = 5

  24. It looks that the popular tests of uniformity do not lead to efficient monitoring of the mean and variability changes, especially when the variability of the process decreases.

  25. Next, we consider Fisher’s method of combining tests. Let

  26. Then

  27. ARL Based on Fisher’s TestWhen n = 5

  28. We see that Fisher’s test leads to a chart that is better than the (X-bar, S) combination for monitoring mean changes and variability increases.

  29. However, this chart can hardly detect any variability decreases.

  30. Finally, we consider the likelihood ration test of the simple nullH0: Mean  and SD  versus the composite alternativeH1: Mean  and/or SD  .

  31. ARL Based on Likelihood Ratio Test When n = 5

  32. We see that the likelihood ratio test leads to a chart that has more balanced performance monitoring the mean and variability changes than the (X-bar, S) combination or any of the cases considered.

  33. To understand better, let’s have a look at the likelihood ratio statistic

  34. Conclusion:Mean  and standard deviation  are functionally related under the normality assumption, even though and are statistically independent.

More Related