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PRESS F5 TO START. This presentation contains Intermediate 2 past paper questions complete with solutions for the year 2006. The questions are sorted into topics based on the specific outcomes for the Intermediate 2 course.

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  1. PRESS F5 TO START This presentation contains Intermediate 2 past paper questions complete with solutions for the year 2006. The questions are sorted into topics based on the specific outcomes for the Intermediate 2 course. To access a particular question from the main grid click on the question number. To get the solution for a question press the space bar. To access the formula sheet press the button To begin click on Main Grid button. F Main Grid

  2. Formulae List START Page

  3. This is the formula that is taught by most teachers these days

  4. 2006 Paper 1 Main Grid Solution

  5. Main Grid

  6. Solution Main Grid

  7. 19 22 19 22 20 21 17 19 21 16 20 19 18 18 20 20 23 19 18 17 19 Solution Main Grid

  8. (b) (i) median (11th) = 19 (ii) Lower Quartile = 18 (iii) Upper Quartile = 20.5 (c) Prob (>18 absent) = Main Grid

  9. Solution Main Grid

  10. Solution Main Grid

  11. Sin200°, Sin0°, Sin30° See graph Sin30 Sin 0 Sin200 Solution Main Grid

  12. Solution Main Grid

  13. (3, -4) • x = 3 • (5, 0) Main Grid

  14. Solution Main Grid

  15. y = Cos(x – 30)° a = 30° Phase shift of 30° i.e. Cos graph has been ‘moved’ 30° to the right. 30° Main Grid

  16. Solution Main Grid

  17. Solution Main Grid

  18. 2006 P2 Solution Main Grid

  19. 4x + 2y = 13 x3 eq1 5x + 3y = 17 x2 eq2 12x + 6y = 39 10x + 6y = 34 2x = 5 subtracting x = 2.5 Sub into eq1 4 x 2.5 + 2y = 13 2y = 13 – 10 = 3 y = Check eq2 5 x 2.5 + 3 x = 12.5 + 4.5 = 17 √ Main Grid Solution

  20. Solution Main Grid

  21. Q3 Main Grid

  22. 9 9 x 15 15 Pythagoras shorter side Solution Main Grid

  23. Solution Main Grid

  24. Yes system is operating effectively as Mean is 20.5°C which is < 20.6°C (max temp allowed) Standard deviation is 1.52°C which is < 2°C (max standard deviation allowed) Main Grid

  25. Solution Main Grid

  26. Solution Main Grid

  27. Solution Main Grid

  28. R Q 6 10 a° P a° = ½ of angle QPR Main Grid

  29. Solution Main Grid

  30. Solution Main Grid

  31. D = SxT = 5.3 x 6 = 16.8 km 100° A 16.8km 80° C 70° B Speed = D÷T = 17.61÷3 = 5.87 km/h Bob is faster by 5.87 – 5.6 = 0.27 km/h Main Grid

  32. Solution Main Grid

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  35. √ √ S A T C Main Grid

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