1 / 11

Chapter 6 TEST!

Chapter 6 TEST!. Wednesday, February 22, 2012. Review. Solve: |4x – 3| = 22. Review. If y = x 2 + x – 6 has solutions x = 2 and x = -3, then what are the solutions to y = (x + 4) 2 + (x + 4) – 6? . Review. Solve (x + 3) 2 = 25. Review.

golda
Télécharger la présentation

Chapter 6 TEST!

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Chapter 6 TEST! Wednesday, February 22, 2012

  2. Review • Solve: |4x – 3| = 22

  3. Review • If y = x2 + x – 6 has solutions x = 2 and x = -3, then what are the solutions to y = (x + 4)2 + (x + 4) – 6?

  4. Review • Solve (x + 3)2 = 25

  5. Review • Complete the square to turn the equation into vertex form: y = x2 + 7x - 12

  6. Review • Use quadratic formula to solve the following quadratic equation: 3x2 – 5x = x2 + 2

  7. Review • Write the equation of the parabola congruent to y = 3x2 under the translation T 5, -3

  8. Review • Put into a + bi form:

  9. Review • Determine the nature of the solutions for the equation y = -2x2 + 5x + 7

  10. Review • Simplify:

  11. Review • Complete the Square: y = x2 – 9x + 2

More Related