1 / 9

Brian Ericson CEP 810 11/16/09

Angle Pairs. Brian Ericson CEP 810 11/16/09. Corresponding Angles. When lines are NOT II. When lines are II. Finding Corresponding Angles. Given : Line AB II Line CD, m ∠ ɑ=(5x+50) °, m ∠ β =(10x) ° Find : m ∠ ɑ and m ∠ β 5x+50=10x Subtract 5x 50 = 5x Divide by 5 X = 10

gomer
Télécharger la présentation

Brian Ericson CEP 810 11/16/09

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Angle Pairs Brian Ericson CEP 810 11/16/09

  2. Corresponding Angles When lines are NOT II When lines are II

  3. Finding Corresponding Angles Given: Line AB II Line CD, m ∠ ɑ=(5x+50) °, m ∠β =(10x) ° Find: m ∠ ɑ and m ∠β 5x+50=10x Subtract 5x 50 = 5x Divide by 5 X = 10 m ∠ ɑ=(5(10)+50) ° m ∠ ɑ=100 ° m ∠β =(10(10)) ° m ∠β =100 °

  4. Alternate Interior Angles When lines are NOT II When lines are II

  5. Finding Alternate Interior Angles Given: Line AB II Line CD, m ∠ ɑ=(4x) °, m ∠β =(2x+30) ° Find: m ∠ ɑ and m ∠β 2x+30=4x Subtract 2x 30 = 2x Divide by 2 15 = x m ∠ ɑ=(4(15)) ° m ∠ ɑ=60 ° m ∠β =(2(15)+30) ° m ∠β =60 °

  6. Alternate Exterior Angles When lines are NOT II When lines are II

  7. Finding Alternate Exterior Angles Given: Line AB II Line CD, m ∠ ɑ=(x+60) °, m ∠β =(3x) ° Find: m ∠ ɑ and m ∠β x+60=3x Subtract x 60 = 2x Divide by 2 30 = x m ∠ ɑ=((30)+60) ° m ∠ ɑ=90 ° m ∠β =(3(30)) ° m ∠β =90 °

  8. Consecutive Interior Angles When lines are NOT II When lines are II

  9. Finding Consecutive Interior Angles Given: Line AB II Line CD, m ∠ ɑ=(40x+20) °, m ∠β =(30x+20) ° Find: m ∠ ɑ and m ∠β 40x+20+30x+20=180 Combine like terms 70x+40 =180 Subtract 40 70x =140 Divide by 70 X =2 m ∠ ɑ=(40(2)+20) ° m ∠ ɑ=100 ° m ∠β =(30(2)+20) ° m ∠β =80 °

More Related