1 / 12

Stoichiometry Unit Review

Stoichiometry Unit Review. How many grams are equal to 1.50 moles of krypton?. .0179 41.9 83.8 126 9.03 x 10 23. 4. How many moles of cobalt are equal to 4.7 x 10 23 atoms of cobalt?. .080 .78 1.3 46 2.8 x 10 25. 0. How many moles of zirconium are equal to 270 grams of zirconium?.

halima
Télécharger la présentation

Stoichiometry Unit Review

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Stoichiometry Unit Review

  2. How many grams are equal to 1.50 moles of krypton? • .0179 • 41.9 • 83.8 • 126 • 9.03 x 1023 4

  3. How many moles of cobalt are equal to 4.7 x 1023 atoms of cobalt? • .080 • .78 • 1.3 • 46 • 2.8 x 1025 0

  4. How many moles of zirconium are equal to 270 grams of zirconium? • 2.96 • 4.49 • 91.2 • 24,629 • 1.78 x 1024 0

  5. 243.52 grams of antimony is equal to _______ mole(s) of antimony or _______ atom(s) of antimony. • 1; 6.02 x 1023 • 2; 6.02 x 1023 • 2; 1.20 x 1024 • .5; 1.20 x 1024 • 2; 2 0

  6. What is the molar mass of sulfuric acid, H2SO4? • 25 • 49 • 67 • 98 • 194 13

  7. 0 Sodium sulfide and cadmium(II) nitrate undergo a double replacement reaction. What is the mass of cadmium sulfide that can be produced from 5.00 g of sodium sulfide? Na2S + Cd(NO3)2 2 NaNO3 + CdS • 0.34 g • 0.64 g • 4.69 g • 9.38 g • 18.8 g

  8. 0 Hydrogen and nitrogen gases can be combined to form ammonia gas, NH3. How many moles of N2 are required to form 27.0 g of ammonia? 3 H2 + N2 2 NH3 • 0.79 mol • 1.59 mol • 3.17 mol • 44.4 mol • 88.8 mol

  9. How many grams of the excess reactant will remain when 10.0 g of silicon and 100 g of oxygen react?Si + O2 → SiO2 • 0.0 g • 21.5 g • 64.8 g • 88.4 g • 166 g 0

  10. What is the percent yield if 35 grams of SO3 is produced from 50 grams of SO2?2SO2 + O2 → 2SO3 • 15% • 30% • 56% • 80% • 94% 30

  11. Determine the percent yield of hydrogen if 12.5 grams of hydrogen is collected from the reaction of 500 g of zinc with 500 g of HCl.Zn(s) + 2HCl(aq) ↔ H2(g) + ZnCl2(aq) • 14% • 46% • 77% • 91% • 110% 30

  12. Participant Scores

More Related