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Balancing Chemical Reactions

Balancing Chemical Reactions. Balancing Chemical Reactions. Balancing Chemical Reactions Sodium metal plus water Na (s) + H 2 O (l) → NaOH + H 2 (g) Burning Magnesium metal in air Mg (s) + O 2 (g) → MgO (s) & – Al + O 2 → Al 2 O 3 Burning Candle wax

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Balancing Chemical Reactions

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  1. Balancing Chemical Reactions

  2. Balancing Chemical Reactions • Balancing Chemical Reactions • Sodium metal plus water • Na (s) + H2O (l) → NaOH + H2(g) • Burning Magnesium metal in air • Mg (s) + O2(g) → MgO (s) & – Al + O2 → Al2O3 • Burning Candle wax • C40H82(s) + O2(g) → CO2(g) +H2O (g)

  3. Balancing Chemical Reactions

  4. Balancing Chemical Reactions

  5. Balancing Chemical Reactions More Hydrogen atoms on the right than on the left. The only place to get more Hydrogen is from H2O

  6. Balancing Chemical Reactions Now you have more Oxygen on the left than on the right. Multiply the NaOH by 2

  7. Balancing Chemical Reactions Now Hydrogen and Oxygen are balanced but Sodium is not. Multiply the Na on the left by 2

  8. Chemical Reactions

  9. Balancing Chemical Reactions

  10. Balancing Chemical Reactions Note one oxygen on the right and two on the left Multiply the left by 2

  11. Balancing Chemical Reactions After multiplying we see that oxygen is balanced but Now magnesium is not, Multiply Mg by 2.

  12. Balancing Chemical Reactions

  13. Balancing Chemical Reactions

  14. Balancing Chemical Reactions Note there are 3 Oxygen on the right and 2 on the left. The simplest factor for 3 and 2 is 6 so 6 divided by 3 is 2 so multiply Al2O3 by 2 and 6 divided by 2 is 3 so multiply O2 by 3.

  15. Balancing Chemical Reactions After doing the multiplication only Al is left unbalanced Multiply Al by 4 to finish.

  16. Balancing Chemical Reactions

  17. Balancing Chemical Reactions

  18. Balancing Chemical Reactions Odd number of Oxygen on the right and even on the left. Multiply the hydrocarbon on the left by 2.

  19. Balancing Chemical Reactions 80 Carbons make 80 CO2 164 Hydrogen's make 82 waters.

  20. Balancing Chemical Reactions After multiplying out the reactants you end up with 242 Oxygen's on the right that you can get from 121 Oxygen molecules on the left.

  21. Balancing Chemical Reactions

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