1 / 10

Regression Line: Income Prediction and Data Analysis

Learn how to create a scatter plot, find the regression line equation, and predict income using a graphing calculator. Example datasets provided.

ivae
Télécharger la présentation

Regression Line: Income Prediction and Data Analysis

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Splash Screen

  2. Concept

  3. When you find a line that closely approximates a set of data, you are finding a line of fit for the data. An equation of such a line is often called a prediction equation because it can be used to predict one of the variables given the other variable.

  4. Regression Line INCOME The table shows the median income of U.S. families for the period 1970–2002. Use a graphing calculator to make a scatter plot of the data. Find an equation for and graph a line of regression. Then use the equation to predict the median income in 2015. Example 2

  5. Regression Line Step 1 Make a scatter plot. STAT  EDIT Enter the years in L1 and the income in L2. Step 2 Set the viewing window to fit the data. WINDOW  numbers will vary depending on problem Step 3View the scatter plot. 2ND Y= ENTER  SELECT “On”  GRAPH Step 4 Find the equation of the line of regression. STAT  > “CALC”  4 “LinReg(ax + b)”  ENTER TWICE Put information from a and b into the equation y = ax + b Example 2

  6. Regression Line WHAT YOU SHOULD SEE LinReg y=ax + b a=1349.867133 B=-2650768.344 The regression equation is about y = 1349.87x – 2,650,768.34. The slope indicates that the income increases at a rate of about 1350 people per year. The correlation coefficient r is 0.997, which is very close to 1. So, the data fit the regression line very well. Example 2

  7. Regression Line Step 5 Graph the regression equation. Copy the equation to the Y= list and graph. Y=  VARS  5 “Statistics”  >> “EQ”  ENTER Notice the equation is now in your Y= menu. GRAPH Notice that the regression line comes close to most of the data points. As the correlation coefficient indicated, the line fits the data well. Example 2

  8. Regression Line Step 6 Predict using the function. Find y when x = 2015. 2ND CALC  ENTER “value”  type in your x-value If your calculator gives you an error, you will need to reset the window size to accommodate your x-value. Answer: According to the function, the median income in 2015 will be about $69,220. Example 2

  9. The table shows the winning times for an annual dirt bike race for the period 2000–2008.Use a graphing calculator to make a scatter plot of the data. Find and graph a line of regression. Then use the function to predict the winning time in 2015. A.y = –15.75x + 31,890.25; about 154 seconds B.y = –14.75x + 29,825.67; about 104 seconds C.y = –14.6x + 29,604.72; about 186 seconds D.y = –14.95x + 30,233.25; about 99 seconds Example 2

  10. Additional Example The table below shows the years of experience for eight technicians at Lewis Techomatic and the hourly rate of pay each technician earns. a. Draw a scatter plot to show how years of experience are related to hourlyrate of pay. b. Write an equation to show how years of experience (x) are related to hourly rate of pay (y). c. Use the function to predict the hourly rate of pay for 21 years of experience.

More Related