1 / 16

Discrete Structures Lecture 26 Predicate Calculus Read Ch 9.1

Discrete Structures Lecture 26 Predicate Calculus Read Ch 9.1. 8.6(c) without using 8.23, part one. ( V i | 0 ≤ i < n+1: b[i]=0)  b[0]=0 V ( V i | 0 < i < n+1: b[i]=0) 0 ≤ i < n+1 = < Remove abbreviation > 0 ≤ i  i < n+1 = < 0 ≤ i  0=i V 0<i >

Télécharger la présentation

Discrete Structures Lecture 26 Predicate Calculus Read Ch 9.1

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Discrete Structures Lecture 26 Predicate Calculus Read Ch 9.1

  2. 8.6(c) without using 8.23, part one (Vi |0 ≤ i < n+1: b[i]=0) b[0]=0V(Vi |0 < i < n+1: b[i]=0) 0 ≤ i < n+1 = < Remove abbreviation > 0 ≤ i  i < n+1 = <0 ≤ i 0=i V 0<i > (0=i V 0<i)  i < n+1 = < (3.46) Distributivity of  over V > (0 = i  i<n+1) V (0 < i  i<n+1) = < Reintroduce abbreviation > (0 = i  i<n+1) V (0 < i<n+1) = < (3.84a) Substitution > (0 = i  0<n+1) V (0 < i<n+1) < Assump 0≤n;0 ≤ n0<n+1;(3.39) Identity of > 0 = i V (0 < i<n+1)

  3. 8.6(c) without using 8.23 (Vi |0 ≤ i < n+1: b[i]=0) b[0]=0V(Vi |0 < i < n+1: b[i]=0) (Vi |0 ≤ i < n+1: b[i]=0) = < Previous Proof > (Vi |0 = iV0 < i < n+1: b[i]=0) = < (8.16) Range Split > (Vi |0 = i: b[i]=0)V(Vi | 0 < i < n+1: b[i]=0) = < (8.14) One Point Rule > b[0]=0 V (Vi |0 < i < n+1: b[i]=0)

  4. A Note about rangesFor example: 2, …, 15 (a) 2 ≤ i ≤ 15 (b) 2 ≤ i < 16 (c) 1 < i ≤ 15 (d) 1 < i < 16 Number of elements in range is equal to upperBound - lowerBound in (b) & (c). Xerox Parc study, said fewest errors with (b).

  5. Predicate Logic An extension of propositional logic that uses variables of types other than B. Propositional Calculus: reasoning about formulas constructed from boolean variables and operators. Predicate Calculus: More expressive class of formulas.

  6. Predicate Calculus Formula Boolean expression in which some Boolean variables may have been replaced by: • Predicates….whose arguments may be of types other than B. • Universal and Existential Quantifiers

  7. Universal Quantification (9.1) (x | Range :P) Read as "for all x such that the Range holds, P holds."  is idempotent, so universal quantification satisfies range split (8.18)….. (8.13)-(8.21) hold as well.

  8. Trading with Universal Quantification (9.2) Axiom, Trading (x|Range:P)  (x|:Range  P) This axiom allows us to prove trading theorems(9.3 a,b,c)and(9.4 a,b,c,d).

  9. Theorem 9.3 (9.3) Theorem, Trading a)(x|R:P)  (x|:¬R V P) b)(x|R:P)  (x|:R  P  R) c) (x|R:P)  (x|:R V P  P)

  10. Theorem 9.4 (9.4) Theorem, Trading a)(x|Q R:P)  (x|Q:R  P) b)(x|Q R:P)  (x|Q:¬R V P) c)(x|Q R:P)  (x|Q:R  P  R) d) (x|Q R:P)  (x|Q:R V P  P)

  11. Distributivity with  (9.5) Axiom, Distributivity of V over  P V (x|R: Q)  (x|R: P V Q) provided ¬occurs ('x','P')

  12. Problem (9.3) Prove theorem (9.6) (9.6) (x | R : P)  P V (x | :¬R) provided ¬occurs ('x','P') (x |R: P) = <(9.3a) Trading > (x | :¬R V P) = <(9.5) V distributes over  > P V (x | :¬R)

  13. More theorems with  (9.7) Distributivity of  over provided ¬occurs ('x','P') ¬(x|:¬R)  ((x|R:PQ)  P  (x|R:Q)) (Antecedent means the range is not everywhere false) Example: ¬(x|:¬(x=0))  ((x|x=0:PQ)  P  (x|x=0:Q)) ¬(x|:x¹0))  ((x|x=0:PQ)  P  (x|x=0:Q)) ¬(x¹0)  ((x|x=0:PQ)  P  (x|x=0:Q)) (x = 0)  ((x|x=0:PQ)  P  (x|x=0:Q)) Likewise: ¬(x|:¬(x>=0))  ((x|x>=0:PQ)  P  (x|x>=0:Q)) ¬(x|: (x<0))  ((x|x>=0:PQ)  P  (x|x>=0:Q)) (x >= 0)  ((x|x>=0:PQ)  P  (x|x>=0:Q))

  14. More theorems with  (9.8) (x | R : true)  true (9.9) (x|R:PQ)  ((x|R:P)  (x|R:Q))

  15. Weakening, Strengthening for  Think back to 3.76a and 3.76b (9.10) Range weakening/strengthening (x | Q V R : P)  (x | Q : P) (9.11) Body weakening/strengthening (x | R : P  Q)  (x | R : P)

  16. Monotonicity of  (9.12) Monotonicity of  (x | R : Q  P)  ((x | R : Q)  (x | R : P))

More Related