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BANK SOAL PRA-UAS

14. BANK SOAL PRA-UAS. 14.1 SOAL DAN PEMBAHASAN A. Peta Karnaugh. Dengan menggunakan Peta Karnaugh, sederhanakanlah fungsi-fungsi berikut ini:. 1. F  xy  uvy  v x y  vx y  uvx y  uvx y 2. F  vxy  uv xy  vxy  v y  vx y

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BANK SOAL PRA-UAS

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  1. 14 BANK SOAL PRA-UAS 14.1 SOAL DAN PEMBAHASAN A. Peta Karnaugh Dengan menggunakan Peta Karnaugh, sederhanakanlah fungsi-fungsi berikut ini: 1. F xy uvy v x y vx y uvx y uvx y 2. F vxy uv xy vxy v y vx y 3. F uv uvxy uvx uv y ux 4. F uvxy uv y uvx v x y uv x uvx 5. F ux y v x y ux y uv xy 6. F xy uvy v x y vx y uvx y uvx y 7. F uvx uv y uvx vxy v y uv Penyelesaian: 1. Diket F xy uvy v x y vx y uvx y uvx y Ditanya Bentuk sederhananya? Jawab Peta Karnaugh: Jadi hasil bentuk sederhananya adalah: F = x + uv + vy 2. Diket F vxy uv xy vxy v y vx y Ditanya : Bentuk sederhananya? Jawab 1 http://www.mercubuana.ac.id

  2. Bab XIV. Bank Soal Pra-UAS Jadi hasil bentuk sederhananya adalah: F = ux +uy + uv 5. Diket F ux y v x y ux y uv xy Ditanya Bentuk sederhananya? Jawab Peta Karnaugh: Jadi hasil bentuk sederhananya adalah: F = x + uv + vy 6. Diket F xy uvy v x y vx y uvx y uvx y Ditanya Bentuk sederhananya? Jawab Peta Karnaugh: 3 http://www.mercubuana.ac.id Modul Logika Matematika, harni_kus@yahoo.com

  3. Bab XIV. Bank Soal Pra-UAS 2. Buatlah tabel kebenaran untuk rangkaian logika di bawah ini! p F = .... q r Penyelesaian F = ( p q) .(q + r) Tabel Kebenarannya: 3. Buatlah tabel kebenaran untuk rangkaian logika di bawah ini! p 5 F = .... q r Penyelesaian F = ( p . q) + (q . r) Tabel Kebenarannya: http://www.mercubuana.ac.id Modul Logika Matematika, harni_kus@yahoo.com

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