1 / 9

Thin Lens Problems

Thin Lens Problems. 87-88. 1. The following data is from an experiment done with a thin converging lens. Use it to determine the image distance produced when the object is 25.0 cm from the same lens. . Givens:. d o = 25.0 cm. Unknown:. d i = ?. What do we need to find first? .

kamali
Télécharger la présentation

Thin Lens Problems

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Thin Lens Problems 87-88

  2. 1 The following data is from an experiment done with a thin converginglens. Use it to determine the image distance produced when the object is 25.0 cm from the same lens. Givens: do= 25.0 cm Unknown: di= ? What do we need to find first? First: Equation:

  3. 1 The following data is from an experiment done with a thin converginglens. Use it to determine the image distance produced when the object is 25.0 cm from the same lens. Givens: do= 25.0 cm Unknown: di= ? di= 14.0 cm Equation:

  4. 2 Corrective lens prescriptions are given in “diopters.” A diopter is simply the reciprocal of the focal length of the lens (measured in meters). For example, a pair of reading glasses with a prescription of +2.25 would have lenses with focal lengths of 1/2.25 = 0.444 m. How tall would the image of a meter stick be if it were placed 75 cm from a pair of glasses with a prescription of -3.75 diopters? Givens: Equation: do1= 75 cm = 0.75 m prescription= -3.75 m What do we need to find first? Find f, in order to find di ho= 1 m = 100 cm Unknown: f= -26 cm hi = ?

  5. 2 Corrective lens prescriptions are given in “diopters.” A diopter is simply the reciprocal of the focal length of the lens (measured in meters). For example, a pair of reading glasses with a prescription of +2.25 would have lenses with focal lengths of 1/2.25 = 0.444 m. How tall would the image of a meter stick be if it were placed 75 cm from a pair of glasses with a prescription of -3.75 diopters? Givens: Equation: do1= 75 cm = 0.75 m prescription= -3.75 m Find di ho= 1 m = 100cm f= -26 cm Unknown: di= -20 cm hi = ?

  6. 2 Corrective lens prescriptions are given in “diopters.” A diopter is simply the reciprocal of the focal length of the lens (measured in meters). For example, a pair of reading glasses with a prescription of +2.25 would have lenses with focal lengths of 1/2.25 = 0.444 m. How tall would the image of a meter stick be if it were placed 75 cm from a pair of glasses with a prescription of -3.75 diopters? Equation: Givens: do1= 75 cm = 0.75 m prescription= -3.75 m Solve: ho= 1 m f= -26 cm Unknown: Solution: hi= 27cm hi = ?

  7. 3 The human eye has a lens system that produces real images on the retina (1.7 cm in back of the lens). In order to focus on objects at a variety of distances from the eye, the lens must be able to change its focal length. What is the change in focal length of the eye’s lens system when you look up from a book 35 cm away to glance across a classroom 15 m away? Givens: Equation: do1= 35 cm What is finital? do2= 15 m = 1500 cm fi= 1.6 cm di= 1.7cm ffinal= 1.7cm Unknown: Δf= 0.1 cm Δf = ffinal– finital =?

  8. 6 Two thin lenses, one a converging lens with a 14.0 cm focal length and the other a diverging lens with a 5.00 cm focal length are placed 18.0 cm apart. An object is placed 20.0 cm to the left of the converging lens (which is the closest lens). Determine the overall magnification. Givens: Equation: do1= 35 cm What is finital? do2= 15 m = 1500 cm fi= 1.6 cm di= 1.7cm ffinal= 1.7cm Unknown: Δf= 0.1 cm Δf = ffinal– finital =?

More Related