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Metabolic Equations

Metabolic Equations. ACSM Formulas. Conversion Factors used in Metabolic Calculations. 1 KG= 2.2 lb 160 lb /2.2=72.7 kg 60 kgX 2.2=132 lb 1 mph= 26.8 meters per minute 6.0 mph x 26.8 = 160.8 m.min. Conversions, cont. Min/mile pace= 60 min/mph

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Metabolic Equations

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  1. Metabolic Equations ACSM Formulas

  2. Conversion Factorsused in Metabolic Calculations • 1 KG= 2.2 lb • 160 lb/2.2=72.7 kg 60 kgX 2.2=132 lb • 1 mph= 26.8 meters per minute • 6.0 mph x 26.8 = 160.8 m.min

  3. Conversions, cont. • Min/mile pace= 60 min/mph • 60 min/7mph= 8.6 min/mile or 8:36 min:sec/mile • 60 sec x 0.6 min= 36 sec • 1 L = 1000 ml • 1 L of O2= 5 kcal • 1 MET = 3.5 ml . Kg . Min • 1 MET = 1 kcal . Kg . Hr • 1 Watt= 6 kgm.min • 540 kgm/6 = 90 Watts • kgm.min= kg x 6 x rpm (monark cycle)

  4. Metabolic terms: • Absolute VO2= rate of O2 uptake in Liters/min. • Relative VO2= rate of O2 uptake in ml/kg/min. Used to compare VO2 between individuals of different body size. • Gross VO2= total consumption of O2 under any circumstances • Net VO2= O2 consumption rate above resting O2 consumption rate. • Used to describe the caloric cost of exercise

  5. ACSM Leg Ergometry Equation: • For power outputs between 300-1200 kgm/min, or 50-200 watts • VO2= (1.8 x kgm/min)/ M (wt. in kg) + (7) • Or • VO2= (10.8 x watts) / M (wt. in kg) + (7)

  6. ACSM Leg Ergometry Equation • To calculate the energy expenditure of a 62 kg woman cycling at a work rate of 450 kgm.min:

  7. To calculate the energy expenditure of a 62 kg woman cycling at a work rate of 450 kgm.min: VO2= (1.8 x 450)/ 62 + 7 VO2= 810/62 + 7 VO2= 13 + 7 VO2= 20 ml/kg/min

  8. ACSM Walking Equation • For speeds of 50-100 m/min. (1.9-3.7 mph) • VO2= Resting Component + Horizonal Component + Vertical Component • R= 3.5 ml. kg. min. • H=speed (m/min) X 0.1 • V=grade (decimal) X m/min X 1.8 • VO2= (0.1 x S) + (1.8 x S x G) + 3.5 • (H) (V) (R)

  9. ACSM Walking Equation • Calculate VO2 for a 70 kg subject who is walking on the treadmill at a speed of 3.5 mph and a grade of 10%:

  10. Calculate VO2 for a 70 kg subject who is walking on the treadmill at a speed of 3.5 mph and a grade of 10%: 1. Convert speed in mph to m.min (3.5 x 26.8= 93.8) 2. Calculate horizontal component. H = speed (m.min) x 0.1 (93.9 x 0.1 = 9.38 ml.kg.min 3. Calculate vertical component: V= grade (decimal) x speed x 1.8 (.10 x 93.8 x 1.8= 16.88 ml.kg.min 4. Calculate total VO2 by adding H, V, and R (resting) components: VO2= H + V + R (9.38 + 16.88 + 3.5)= 29.76 ml.kg.min Convert VO2 to METS by dividing by 3.5: (29.76/3.5 = 8.5 METS How many kcals burned in 20 minutes?

  11. ACSM Running/Jogging Formula • For speeds > 134 m/min (>5.0 mph), (or for speeds as low as 3mph if jogging) • VO2= Resting Component + Horizontal Component + Vertical Component • R= 3.5 ml.kg.min • H= speed (m/min) X 0.2 • V= grade (decimal) X m/min X 0.9 • VO2= (0.2 x S) + (0.9 x S x G) + 3.5 • (H) (V) (R)

  12. ACSM Jogging/Running Formula • Calculate VO2 for someone running a 7.5 mph. (200 meters/min) With a 5% grade?

  13. Calculate VO2 for someone running at 7.5 mph. (200 meters/min) With a 5% grade? • VO2= 3.5+ (m/min X 0.2) • 43.5= 3.5 + (200 x 0.2) • For uphill running, add: • grade (decimal) x m/min x 0.9 • VO2= 3.5 + (200 x 0.2) + (.05 x 200 x 0.9) • VO2= 52.5

  14. What is the total amount of work on a cycle ergometer • Kpm/min • Joules • With 2-kg resistance, 6 m•rev–1, 60 rev•min–1for 5min

  15. With 2-kg resistance, 6 m•rev–1, 60 rev•min–1 for 5 min 2 kg needs to go to N - 2 X 9.79 = 19.58 19.58 x 6m/rev x 60 revs/min x 5 min 35244 Joules For kpm/min – use 2 kg and do not convert to N 3600 kpm/min

  16. Calculate the avg. power output during 10 min of cycle ergometer Exercise in which a total of 10,000 kpm of work was performed Answer in kpm/min and Watts

  17. Calculate the avg. power output during 10 min of cycle ergometer exercise in which a total of 10,000 kpm of work was performed. Answer in kpm/min and Watts Work = Force X Distance Power = Force X Distance divided by time 10,000 kpm of work Divide by 10 min 1,000 kpm/min 1,000/6 = 166.7 Watts 1 Watt = 6 kgm/min

  18. Calculate the work during 2-min of treadmill exercise by a 60-kg person running at 200 meters/min up a 10 % grade.

  19. Calculate the work during 2-min of treadmill exercise by a 60-kg person running at 200 meters/min up a 10 % grade. • Vertical displacement = % grade x distance 0.1 x (200 m•min–1x 2min) = 40 m • Work = body weight x total vertical distance 60 kg x 9.79 = 587.4 N 587.4 N x 40 m = 23496 J • Power = work ÷ time 23496 J ÷ 120 s = 195.8 W

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