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改 错

改 错. 1 、取 {2m, 3n |m≥1 , n≥1} 中由小到大排列的前 70 项数。 #include<stdio.h> void main( ) {double m,n; int k; /**********error************/ m=2, n=3; for(k=0;k<70;k++) /**********error************/ if(n<m) {printf("%40.0f",m); m*=2; } else {printf("%40.0f",n);

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改 错

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  1. 改 错

  2. 1、取{2m, 3n |m≥1,n≥1}中由小到大排列的前70项数。 #include<stdio.h> void main( ) {double m,n; int k; /**********error************/ m=2, n=3; for(k=0;k<70;k++) /**********error************/ if(n<m) {printf("%40.0f",m); m*=2; } else {printf("%40.0f",n); n*=3; } return; } m=2;n=3; if(m<n)

  3. 2、求 1- 1/2+1/3-1/4+…+ 1/99-1/100 的值。 #include<stdio.h> void main() {int i,t; float s=0; for (i=t=1;i<=100;i++) { /***********error*************/ s+=t/i; t=-t; } /***********error************/ printf("s=%d\n",s); } s+=(float)t/i; printf("s=%f\n",s);

  4. 3、任意输入一串字符,以“?”结束,分别统计其中字母、数字和其他字符的个数。3、任意输入一串字符,以“?”结束,分别统计其中字母、数字和其他字符的个数。 #include<stdio.h> void main() {char c; int n1=0,n2=0,n3=0; /***********error************/ for((c=getchar())!='?') /***********error************/ if((c>='A'&&c<='Z')&&(c>='a'&&c<='z'))n1++; else if(c>='0'&&c<='9')n2++; else n3++; printf("%d,%d,%d\n",n1,n2,n3); } for(;(c=getchar())!='?';) if((c>='A'&&c<='Z')||(c>='a'&&c<='z'))n1++;

  5. 7、程序的功能是把两个字符串连接起来,请改正程序中的错误。7、程序的功能是把两个字符串连接起来,请改正程序中的错误。 #include<stdio.h> void main() { char s1[100],s2[40]; int i=0,j=0; printf("\n please input string1\n"); scanf("%s",s1); printf(" please input string2\n"); scanf("%s",s2); while(s1[i]!='\0') i++; /***********error************/ while(s2[j]='\0') s1[i++]=s2[j++]; /***********error************/ s1[i]="\0"; printf("linked string:%s",s1); } le(s2[jwhi]!='\0') s1[i]='\0';

  6. 8、程序的功能是判断输入的字符串是否是“回文”,若是“回文”,输出“yes”,否则输出“no”。,请改错:8、程序的功能是判断输入的字符串是否是“回文”,若是“回文”,输出“yes”,否则输出“no”。,请改错: void main() {char s[81],cr,*pi,*pj; int n; gets(s); n=strlen(s); pi=s;pj=s+n-1; while(*pi==' ') pi++; while(*pj==' ') pj--; while((pi<pj)&&(*pi==*pj)) {pi++;pj--;} /***********error************/ if(pi!=pj) printf("NO\n"); else printf("YES\n");} if(pi<pj) printf("NO\n");

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