1 / 43

DNA Computer ~ 回顧 Leonard M. Adleman 之研究

DNA Computer ~ 回顧 Leonard M. Adleman 之研究. 化工系 F88524017 洪仕馨. DNA Computer 之優點. Low energy consumption Less space Efficient Accurate : :. 摘要. Use DNA to solve the “Hamiltonian Path Problem” DNA Computer (a) the unrestricted (DNA) model (b) A sticker Based Model.

leone
Télécharger la présentation

DNA Computer ~ 回顧 Leonard M. Adleman 之研究

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. DNA Computer~回顧Leonard M. Adleman之研究 化工系 F88524017 洪仕馨

  2. DNA Computer之優點 • Low energy consumption • Less space • Efficient • Accurate • : :

  3. 摘要 • Use DNA to solve the “Hamiltonian Path Problem” • DNA Computer (a) the unrestricted (DNA) model (b) A sticker Based Model

  4. 1. Computing with DNA 1994 Leonard M. Adleman Use DNA to Solve the “Hamiltonian Path Problem”

  5. Hamiltonian Path Problem 如同“Traveling Salesman Problem” 由A到G,每個城市都要經過,只經過一次,且只能依照箭頭方向前進

  6. 傳統的解題步驟 Step 1: Generate a set of random paths through the graph. Step 2:Check wheather that path starts at the start vertex and ends with the end vertex. If not,remove that path from the set. Step 3: Check if that path passes through exactly n vertices. If not,remove that path from the set. Step 4: For each vertex, check if that path passes through that vertex. If not,remove that path from the set. Step 5: If the set is not empty,then report that there is a Hamiltonian path. If the set is empty, report that there is no Hamiltonian path.

  7. When the number of cities is increased to 70, the problem becomes too complex for even a supercomputer. 解決方法 : ~ DNA Computation ~

  8. A : adenine T : thymine C : guanine G : cytosine What is DNA

  9. Watson-Crick pairing If a molecule of DNA in solution meets its Watson-Crick complement, then the two strands will anneal---twist around each other to form the famous double helix.

  10. Programming with DNA 為簡化題目,此處只考慮四個城市,六種航線飛機

  11. 解法:Step 1 Create a unique DNA sequence for each city A through G. For each path, for example, from A to B, create a linking piece of DNA that matches the last half of A and first half of B

  12. Step 2 Watson-Crick pairing Mix the DNA with flight number and complement DNA with city name in a test tube, with some of these DNA strands sticking together. A chain of these strainds represents a possible answer.

  13. Watson-Crick pairing

  14. Watson-Crick pairing

  15. Step 3: polymerase chain reaction Because it is difficult to “remove” DNA from the solution, the target DNA ( start at A and end at G) was copied over and over again until the test tube contained a lot of it relative to the other random sequences.

  16. Step 4: Gel electrophoresis • Separates DNA by length. • 7 “cities” long were separated from the rest.

  17. Step 5: Purified 例:想去掉沒有含A的DNA,可以利用含有A城市名的DNA將會和complement A 城市的 DNA結合,其餘不會. 去掉沒經過A的 B : G ------------------------------------- 剩下ABCDEFG都有經過的

  18. Step 6 All that was left was to sequence the DNA, revealing the path from A to B to C to D to E to F to G.

  19. 2. DNA computer • the unrestricted (DNA) model 1995 Leonard M. Adleman “ On Constructing A Molecular Computer”

  20. (a)the unrestricted (DNA) model A (test) tube is a set of molecules of DNA ( i.e. a multi-set of finite strings over the alphabet {A,C,G,T}) ,對於此test tube T , 有四種 operations:

  21. 1. Separate Give a tube T and a string of symbols S over {A,C,G,T}, produce two tubes: (1) +(T,S) --> all of the molecules of DNA in T which contain the S (2) -(T,S) --> all of the molecules of DNA in T which do not contain the S 在 molecular biology 技術上, 可使用 affinity column 分離。

  22. 2. Merge Give tubes T1,T2, produce (T1,T2) where: (T1,T2)=T1  T2 即將T1和T2混在一起,成為(T1,T2)=T1  T2

  23. 3. Detect Detect 如果試管內含有任何 DNA molecule, 則為 "yes" 否則為 "no"。 可用 PCR, 及光譜偵測。

  24. 4. Amplify Give a tube T produce two tubes T’(T) and T”(T) such that T=T’(T)=T”(T). 複製T’(T),T”(T)使得T=T’(T)=T”(T)

  25. Write ‘programs’ For example:假設DNA分子只由A構成,傳回“yes”,否則,傳回“no” • Input (T) • T1=-(T,C) 去掉含有C的DNA分子 • T2=-(T1,G) G • T3=-(T2,T) T • Output( Detect(T3)) ……………..”yes”

  26. 2. DNA computer (b) 1996 S. Roweis, E. Winfree: Computation and Neural Systems Option R. Burgoyne: Department of Biomedical Engineering N. F. Goodman: Department of Biological Science N. V. Chelyapov, P. W. K. Rothemund, L. M. Adleman : Department of Computer Science “A Sticker Based Model for DNA Computation”

  27. A Sticker Based Model for DNA Computation 有和stickers鍵結者為“1”,沒有為“0”

  28. Four principle operations 1. Combination of two sets of strings into one new set

  29. 2. Separation of one set of strings into two new sets

  30. 3. Setting (turn on) a particular bit in every string of a set

  31. 4. Clearing(turn off) a bit in every string of a set

  32. (1) A closed cylinder with a nipple connector in either end that allows fluid to flow in or out. (2) Near one end on the inside is a permanent membrane which passes solvent but not stickers or memory strands. Data Tube

  33. Operator Tubes: Separation (1) Separation operator tube contains many identical copies of one bit’s oligo probe. It is designed so that the probes cannot escape from the tube but unbound memory complexes can.

  34. Operator Tubes: Sticker (2) A sticker operator tube is identical expect for a permanent filter on its inside which passes stickers but not memory strands.

  35. Operator Tubes: Blank (3) A blank operator tube is merely empty tube with nipple connectors on each end.

  36. Setup for a generic operation in the stickers machine The dirty sides of the data tubes are connected to the operator tube; the clean sides of the data tubes are joined by a pump. Solution is cycled through all three tubes. The temperature, salinity, direction and duration of the flow is controlled by the electronic computer.

  37. To combine two sets of complexes simply select the two data tubes and a blank operator tube. Cycle cold solution towards (say) the first data tube. This catches all the memory complexes in the first data tube. The second data tube and the blank operator are discarded. Combination

  38. By control the temperature and direction of the flow to separate a set of complexes. Separation

  39. Set Bit Clear Bit

  40. 結論 Computation with DNA is possible. Will we succeed in creating molecular computers that can compete with electronic computers???

  41. Challenges In biology and chemistry: challenges in understanding cellular and molecular mechanisms and making them available for use. In computer science and mathematics: challenges in finding appropriate problems and efficient molecular algorithms to solve them. In physics and engineering: challenges in building large scale, reliable molecular computers.

  42. References • Leonard Adleman: Molecular computation of solutions to combinatorial problems. Science, 266:1021-1024. (Nov. 11). 1994. • M. Linial, N. Linial, Y. M. D. Lo, K. F. C. Yiu, S. L. Wong, B. Bunow, L. M. Adleman, Science, 268, 5210, 481-484 ,1995. • Leonard Adleman: On constructing a molecular computer, DNA Based Computers, Eds. R. Lipton and E. Baum, DIMACS: series in Discrete Mathematics and Theoretical Computer Science, American Mathematical Society. 1-21 ,1996. • S. Roweis, E. Winfree, R. Burgoyne, N. V. Chelyapov, N. F. Goodman, P. W. K. Rothemund, L. M. Adleman,”A sticker Based Model for DNA computation”,1996. • L. M. Adleman, Science American, Aug. , 34-41 (1998).

More Related