1 / 8

8 th Period Gen Phys

8 th Period Gen Phys. Get out your notebook, pen/pencil and worksheet. Leave ALL other materials at the front (including phones- if I see them I will take them!) Open your notebook to your notes from yesterday. Lesson 4. Equivalent Equations: Sums and Differences. Objective:

macey-vaughan
Télécharger la présentation

8 th Period Gen Phys

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. 8th Period Gen Phys • Get out your notebook, pen/pencil and worksheet. • Leave ALL other materials at the front (including phones- if I see them I will take them!) • Open your notebook to your notes from yesterday.

  2. Lesson 4 Equivalent Equations: Sums and Differences Objective: Identify and solve equations involving a sum and two addends.

  3. The sum equals one addend plus the other addend. One addend equals the sum minus the other addend. 8= 5 + 3 8= 3 + 5 5 + 3 = 8 3 + 5 = 8 8 –5 = 3 8 –3 = 5 3 = 8 –5 5 = 8 –3 How are the top four equations similar? The top four equations are explicit for the sum. How are the bottom four equations similar? The bottom four equations are explicit for one of the addends.

  4. Here are the two basic patterns: [sum] = [one addend] + [other addend] [one addend] = [sum] – [other addend]

  5. [sum] = [one addend] + [other addend] [one addend] = [sum] – [other addend] Example: The equation 4 + 7 = 11 is solved explicitly for the sum 11. Solve the equation for 4 and 7, but do not compute. 4 + 7 = 11 To solve for 4, we note that it is an addend. How do we solve for an addend? So the addend 4, is equal to the sum 11 minus the other addend 7. 4 = 11 – 7 Likewise, to solve for the addend 7, we write the sum 11 minus the other addend 4: 7 = 11 – 4

  6. [sum] = [one addend] + [other addend] [one addend] = [sum] – [other addend] Example: The equation 6 = 15 – 9 is solved explicitly for the addend 6. Solve the equation for 15 and 9, but do not compute. 6 = 15 – 9 To solve for 15, we note that it is the sum. How do we solve for the sum? So, the sum 15 is found by adding the two addends together (in either order). 15 = 9 + 6 15 = 6 + 9 or To solve for the addend 9, we use the other pattern. 9 = 15 – 6 The addend 9 is equal to the sum 15 minus the other addend 6: Note: We can go from the original equation to the final equation in one step.

  7. Application (Sales): Susan bought a book that cost $6.75 and paid for it with a $10 bill. The clerk counted out her change of $3.25 as follows: He handed her 25¢ and said, “That makes $7.00.” Then he handed her a dollar and said, “$8.00,” then another dollar and said, “$9.00,” and finally one last dollar and said, “That makes $10.00.” The clerk was illustrating that [Cost] + [Change] = [Payment] $6.75 + = $3.25 $10.00 Without computing, solve this equation explicitly for the $3.25 change. The Payment is the sum, and the Cost and Change are the addends. [one addend] = [sum] – [other addend] $3.25 = – $10.00 $6.75 [Change] = [Payment] – [Cost]

  8. Remember: [sum] = [one addend] + [other addend] [one addend] = [sum] – [other addend]

More Related