1 / 21

Gas Stoichiometry Ideal Gas Law

Gas Stoichiometry Ideal Gas Law. Putting it all together…. Balance the following equation…. C 8 H 18 (l) + O 2 (g) → CO 2 (g) + H 2 0(g) 2 C 8 H 18 (l) + 25 O 2 (g) → 16 CO 2 (g) + 18 H 2 0(g) Coefficients of balanced equations can be used as mole ratios in stoichiometry problems.

Télécharger la présentation

Gas Stoichiometry Ideal Gas Law

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Gas Stoichiometry Ideal Gas Law Putting it all together…

  2. Balance the following equation… • C8H18(l) + O2(g) → CO2(g) + H20(g) • 2 C8H18(l) + 25 O2(g) → 16 CO2(g) + 18 H20(g) • Coefficients of balanced equations can be used as mole ratios in stoichiometry problems

  3. Mass-Mass Stoichiometry • Problem 11.13 c (p.332) • Mg + HCl → H2 + MgCl2 • 60.1 g HCl

  4. Volume Ratio = Mole Ratio • Problem 12.85 (p.373) • 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g)

  5. Avogadro’s LawOne mole of a gas will occupy 22.4 L • This means that the mole ratio is the same as the volume ratio

  6. Volume Ratio = Mole Ratio • Problem 12.85 (p.373) • 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g) • 200. L O2

  7. Volume Ratio = Mole Ratio • Problem 12.85 (p.373) • 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g) • Problem 12.81 (p.373) • 2 C2H2(g) + 5 O2(g) → 4 CO2(g) + 2H2O(g) • 2.5 tanks O2

  8. Gas @ STP • Problem 12.92 (p374) • NaN3(s) + Fe2O3(s) → Na2O(s) + Fe(s) + N2(g) • 6 NaN3(s) + Fe2O3(s) → 3 Na2O(s) + 2 Fe(s) + 9 N2(g) • 10.6 g NaN3

  9. Standard Molar Volume • The volume of 1.0 mole of any gas at STP is 22.4 L. • This is called the standard molar volume. • The volume of any gas at STP can be calculated if the number of moles is known: • V = (moles)(22.4 L)

  10. Gas Not at STP • Problem 12.88 (p.373) • CaC2(s) + 2 H2O(l) → Ca(OH)2(s) + C2H2(g)

  11. Ideal Gas Law • All of the variables used to describe gases can be compared using the Ideal Gas Law • The IGL is often called an equation of state, as it is very useful when finding some property of a gas at a certain condition • Not so great when conditions are changing • Entropy is another condition of state

  12. Ideal Gas Law • PV = nRT • P = pressure • V = volume • T = temperature • n = number of moles of gas • R = Gas Constant • value depends on the desired unit

  13. Gas Constant (“R”) • R is a constant that is used in the IGL so that it may be used for all gases • It has a different value, depending on the pressure unit being used in the problem

  14. Gas Not at STP • Problem 12.88 (p.373) • CaC2(s) + 2 H2O(l) → Ca(OH)2(s) + C2H2(g) • 960 ml C2H2 • Problem 12.90 (p.373) • 2 C8H18(l) + 25 O2(g) → 16 CO2(g) + 18 H20(g)

  15. Gas Not at STP • Problem 12.88 (p.373) • CaC2(s) + 2 H2O(l) → Ca(OH)2(s) + C2H2(g) • 960 ml C2H2 • Problem 12.90 (p.373) • 2 C8H18(l) + 25 O2(g) → 16 CO2(g) + 18 H20(g) • 837 L CO2

More Related