1 / 12

VEDIC MATHEMATICS : Divisibility

VEDIC MATHEMATICS : Divisibility. T. K. Prasad http://www.cs.wright.edu/~tkprasad. Divisibility. A number n is divisible by f if there exists another number q such that n = f * q. f is called the factor and q is called the quotient . 25 is divisible by 5

missy
Télécharger la présentation

VEDIC MATHEMATICS : Divisibility

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. VEDIC MATHEMATICS : Divisibility T. K. Prasad http://www.cs.wright.edu/~tkprasad Divisibility

  2. Divisibility • A number n is divisible by f if there exists another number q such that n = f * q. • f is called the factor and q is called the quotient. • 25 is divisible by 5 • 6 is divisible by 1, 2, and 3. • 28 is divisible by 1, 2, 4, 7, 14, and 28. • 729 is divisible by 3, 9, and 243. Divisibility

  3. Divisibility by numbers • Divisibility by 1 • Every number is divisible by 1 and itself. • Divisibility by 2 • A number is divisible by 2 if the last digit is divisible by 2. • Informal Justification (for 3 digit number): pqr = p * 100 + q * 10 + r Both 100 and 10 are divisible by 2. Divisibility

  4. (cont’d) • Divisibility by 4 • A number is divisible by 4 if the number formed by last two digits is divisible by 4. • Informal Justification (for 3 digit number): pqr = p * 100 + q * 10 + r 100 is divisible by 4. • Is 2016 a leap year? • YES! Divisibility

  5. (cont’d) • Divisibility by 5 • A number is divisible by 5 if the last digit is 0 or 5. • Informal Justification (for 4 digit number): apqr = a * 1000 + p * 100 + q * 10 + r 0, 5, 10, 100, and 1000 are divisible by 5. • Is 2832 divisible by 5? • NO! Divisibility

  6. (cont’d) • Divisibility by 8 • A number is divisible by 8 if the number formed by last three digits is divisible by 8. • Informal Justification (for 4 digit number): apqr = a * 1000 + p * 100 + q * 10 + r 1000 is divisible by 8. • Is 2832 divisible by 8? • YES! Divisibility

  7. (cont’d) • Divisibility by 3 • A number is divisible by 3 if the sum of all the digits is divisible by 3. • Informal Justification (for 3 digit number): pqr = p * (99+1) + q * (9+1) + r 9 and 99 are divisible by 3. • Is 2832 divisible by 3? • YES because (2+8+3+2=15) is, (1+5=6) is …! Divisibility

  8. (cont’d) • Divisibility by 9 • A number is divisible by 9 if the sum of all the digits is divisible by 9. • Informal Justification (for 3 digit number): pqr = p * (99+1) + q * (9+1) + r 9 and 99 are divisible by 9. • Is 12348 divisible by 9? • YES, because (1+2+3+4+8=18) is, (1+8=9) is, …! Divisibility

  9. (cont’d) • Divisibility by 11 • A number is divisible by 11 if the sum of the even positioned digits minus the sum of the odd positioned digits is divisible by 11. • Informal Justification (for 3 digit number): pqr = p * (99+1) + q * (11-1) + r 11 and 99 are divisible by 11. • Is 12408 divisible by 11? • YES, because (1-2+4-0+8=11) is, (1-1=0) is, …! Divisibility

  10. (cont’d) • Divisibility by 7 • Unfortunately, the rule of thumb for 7 is not straightforward and you may prefer long division. • However here is one approach: • Divisibility of n by 7 is unaltered by taking the last digit of n, subtracting its double from the number formed by removing the last digit from n. • 357 => 35 – 2*7 => 21 Divisibility

  11. Is 204379 divisible by 7? 204379 => 20437 – 18 => 20419 => 2041 – 18 => 2023 => 202 – 6 => 196 => 19 – 12 => 7 Divisibility

  12. (cont’d) • Informal Justification • A multi-digit number is 10x+y (e.g., 176 is 17*(10)+6). • 10x+y is divisible by 7 if and only if20x+2y is divisible by 7. (2 and 7 are relatively prime). • Subtracting 20x+2y from 21x does not affect its divisibility by 7, because 21 is divisible by 7. • But (21x – 20x – 2y) = (x – 2y). • So (10x+y) is divisible by 7 if and only if (x-2y) is divisible by 7. Divisibility

More Related