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Homework 2-2 #14

Step 1. MI = LD 2. IL = IL 3. MI + IL = LD + IL 4. MI + IL = ML; LD + IL = ID 5. ML = ID. Reason 1. Given 2. Reflexive Property 3. Addition Property 4. Segment Addition Postulate 5. Substitution. M. I. L. D. Homework 2-2 #14. 2-2 PROOFS. STEP 1. 3x = 7 – 1/2x

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Homework 2-2 #14

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  1. Step 1. MI = LD 2. IL = IL 3. MI + IL = LD + IL 4. MI + IL = ML; LD + IL = ID 5. ML = ID Reason 1. Given 2. Reflexive Property 3. Addition Property 4. Segment Addition Postulate 5. Substitution M I L D Homework 2-2 #14

  2. 2-2 PROOFS

  3. STEP 1. 3x = 7 – 1/2x 2. 6x = 14 – x 3. 7x = 14 4. x = 2 REASON 1. GIVEN 2. Multiplication Property 3. Addition Property 4. Division Property Proof I will give you the 1st step First reason is always “given”

  4. Step 1. 2x + 3 = 11 2. 2x = 8 3. x = 4 Reason 1. Given 2. Subtraction Property 3. Division Property TOO: 3 Steps

  5. Step 1. RS = PS, ST = SQ 2. RS + ST = PS + SQ 3. RS + ST = RT PS + SQ = PQ 4. RT = PQ Reason 1. Given 2. Addition Property 3. Segment Addition Postulate 4. Substitution R P Example: Geometry Proof Given: RS = PS and ST = SQ Prove: RT = PQ S Q T

  6. Step 1. 2. 3. 4. 5. Reason 1. Given 2. Angle Addition Postulate 3. Substitution Property 4. Reflexive Property 5. Subtraction Property A B TOO: 5 Step Proof Given: Prove: C 1 2 O 3 D

  7. Homework • Page 41 #1-14 • #11-14 are each 4 step proofs • Flash Cards • Reflexive Property • Substitution

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