1 / 6

Unit: Thermochemistry

Day 4 - Notes. Unit: Thermochemistry. Limiting Reactants and Thermochemical Equations. After today you will be able to…. Use thermochemical equations to calculate limiting reactant. Recall, a limiting reactant is the reactant which yields the smaller amount of product.

owen-clark
Télécharger la présentation

Unit: Thermochemistry

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Day 4 - Notes Unit: Thermochemistry Limiting Reactants and Thermochemical Equations

  2. After today you will be able to… • Use thermochemical equations to calculate limiting reactant

  3. Recall, a limiting reactant is the reactant which yields the smaller amount of product. • Energy in a chemical reaction can also help to determine which reactant limits the amount of product that can be made.

  4. Example: How much energy is used when 14.3 moles of hydrosulfuric acid reacts with 17.1 moles of oxygen gas? 2H2S + 3O2 + 175 KJ  2SO2 + 2H2O 14.3 mol H2S x _________ = 17.1 mol O2 x ________ = K: 14.3 mol H2S U: ? kJ + 175 kJ +1250 kJ 2 mol H2S K: 17.1 mol O2 Used: U: ? kJ + 175 kJ +998 kJ 3 mol O2

  5. 3 2 1 Example: How much energy is produced when 13.11g of tin reacts with 2.715g of nitrogen? __ Sn + __ N2 __ Sn3N4 + 632 KJ 13.11 gSn x _________ x ________ = 2.715 gN2 x ________ x ________ = K: 13.11 gSn U: ? kJ Produced: 1 mol Sn -632 kJ -23.27 kJ 118.71 gSn 3 mol Sn K: 2.715 gN2 U: ? kJ 1 mol N2 -632 kJ -30.62 kJ 28.02 gN2 2 mol N2

  6. Questions? Complete WS 4

More Related