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Outline for today’s lecture (Ch. 14, Part I)

Outline for today’s lecture (Ch. 14, Part I). Ploidy vs. DNA content The basis of heredity ca. 1850s Mendel’s Experiments and Theory Law of Segregation Law of Independent Assortment Introduction to Probability. Reminder: Homologous chromosomes. Pair at meiosis (all pairs)

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Outline for today’s lecture (Ch. 14, Part I)

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  1. Outline for today’s lecture (Ch. 14, Part I) • Ploidy vs. DNA content • The basis of heredity ca. 1850s • Mendel’s Experiments and Theory • Law of Segregation • Law of Independent Assortment • Introduction to Probability

  2. Reminder: Homologous chromosomes • Pair at meiosis • (all pairs) • Same sequence (except • sex chromosomes)

  3. 4 “C” (DNA per chromosome) 2 1 G1 S G2 Meiosis I Meiosis II Ploidy vs. DNA content in Meiosis Diploid Haploid Diploid: Contains two chromosomes from a homologous pair one from each parent Haploid: Contains only one chromosome from a homologous pair

  4. The Nature of Heredity, ca. 1859 • Observation: Offspring generally intermediate in phenotype (“trait value”) between those of parents • Obvious example: Human children with one African and one Nothern European parent • Proposed explanation: “Blending Inheritance” • Genetic material miscible, like paint: • Black + White = Gray • Tall + Short = Medium • Etc.

  5. Blending Inheritance: A logical difficulty • Variation reduced every generation • Ultimate consequence is a homogeneous population • At odds with reality • How to explain variation? • “Sports” (Mutation in modern parlance)

  6. Gregor Mendel: The Origin of Genetics • Austrian farm boy, entered Augustinian monastary in 1843 • Attended University of Vienna in early 1850s • Learned two things about science • Do experiments • Analyze your data (i.e., mathematically) • ~1857, began an experimental program to investigate the basis of inheritance (i.e., heredity) with peas

  7. Mendel’s Experiments • Peas were a fortuitous study organism for several reasons: • Many variable characters (e.g., flower color, seed shape, seed color, etc.) • Many varieties that bred “true” for particular traits (e.g., purple flowers, round seeds, etc.) • Easy to do controlled crosses, both “self” and outcross

  8. 1.0 1.0 frequency frequency 0.5 0.5 0.0 0.0 2.0 3.0 4.0 White Black Color Mendel’s Experiments – Choice of characters • Used only discrete characters, i.e., “either-or”, not continuous Height

  9. P Self Self Self Self F1 F2 Mendel’s Experiments – Breeding design • Start with lines that breed true for different traits, e.g., purple and white flowers • First generation of a cross is called P (“parental”) • Offspring are F1 (“filial”) • Grand-offspring are F2

  10. P X Self F1 F2 Mendel’s Experiments – Breeding design • Cross two true-breeding lines (purple, white) • Self F1s • Observe phenotypes of MANY F2 offspring and COUNT THEM

  11. Mendel’s Experiments – Results • Cross two true-breeding lines (purple, white) • F1s ALL PURPLE • What do we expect if “blending inheritance”? P X F1

  12. P X Self F1 F2 Mendel’s Experiments – Breeding design • Cross two true-breeding lines (purple, white) • F1s ALL PURPLE • Self F1s • F2s are NOT all purple – • 705 purple • 224 white • i.e., ~ 3:1 purple : white

  13. P X Self F1 F2 Mendel’s Experiments – Conclusions • “Heritable Factor” (i.e., gene) for white flowers did not disappear in the F1, but only the purple “factor” affected flower color. "Particulate" inheritance • Purple is “dominant” and white is “recessive”

  14. P Self F1 F2 Mendel’s Experiments – Important Points • Followed the pattern of inheritance for multiple generations (i.e., > 1) • What if the experiment terminated after F1? • Quantitative Analysis • Many 19th century botanists would have said “some white flowers reappeared in F2” • Mendel was lucky! X

  15. Mendel’s Experiments in modern genetic terms • Alternative versions of genes account for variation in inherited characters • Alternative versions of genes are “alleles” • Alleles reside at the SAME geneticlocus • Relationship between alleles, chromosomes, and DNA • DNA at a locus varies in sequence • Sequence variants cause different phenotypes (e.g., purple and white flowers)

  16. Mendel’s Experiments in modern genetic terms “Flower-color locus” • Diploid individuals have homologous pairs of chromosomes, one from each parent • An individual inherits one allele from each parent • Alleles may be same or different • If different, the dominant allele determines the organism’s phenotype Purple allele White allele

  17. Mendel’s Experiments in modern genetic terms • The two alleles at a locus segregate during gamete production • Each gamete gets only one of the two alleles present in somatic cells • Segregation corresponds to the different gametes in meiosis (I or II?)

  18. Recall Meiosis I – Metaphase I • What about crossing-over?

  19. Mendel’s “Law of Segregation” • If an individual has identical alleles at a locus (i.e., is true-breeding), that allele is present in all its gametes • If an individual has two different alleles at a locus, half its gametes receive one allele, half receive the other allele All half half

  20. Genetic Terminology – • If a diploid individual has two copies of the SAME ALLELE at a locus (i.e., it got the same allele from mom and dad), it is a HOMOZYGOTE • If it has two different ALLELES at a locus (got a different allele from mom than from dad) it is a HETEROZYGOTE • The genetic makeup at a locus (or loci) is the individual’s GENOTYPE • An organism's Traits comprise its PHENOTYPE

  21. P X Self F1 F2 Mendel’s Law of segregation: a test Genotype: PP x pp Gametes: P p Genotype: Pp Gametes: 1/2 P, 1/2 p Genotype: 1/4 PP, 1/2 Pp, 1/4 pp Phenotype: 3 purple, 1 white

  22. Mendel’s Law of segregation: a test F1 X • Phenotype: • Genotype: Pp Pp • Ova (female gametes) 1/2 P, 1/2 p • Sperm (male gametes) 1/2 P, 1/2 p • Half of male gametes will be P. Of those, half will unite with an ovum that is P. • Thus, the frequency of PP in the F2 is: (1/2)(1/2 ) = 1/4 • Frequency of pp = (1/2)(1/2) = 1/4, • Frequency of Pp = 2(1/2)(1/2) = 1/2

  23. Pp P p Pp P PP Pp p pP pp The “Punnett Square” MaleParent Sperm genotype • Gamete genotypes of one parent given as columns • Gamete genotypes of other parent given as rows • Offspring genotypes given as cells in the table • Each cell has equal frequency (here = 1/4) Female Parent Egg genotype

  24. Pp P p Pp P PP Pp p pP pp The “Punnett Square” MaleParent Sperm genotype • Note that in this cross there are TWO ways to get a heterozygote • P from mom, p from Dad • p from mom, P from Dad • Frequency of heterozygotes = 1/4 Pp + 1/4 pP = 1/2 Female Parent Egg genotype

  25. The “Testcross” MaleParent Sperm genotype • Individuals homozygous for a dominant allele have the same phenotype as heterozygotes • To determine the genotype of an individual, cross it to a known homozygous recessive • What is the phenotypic ratio among these offspring? • What is the genotype of the unknown individual? Female Parent pp p p P- P Egg genotype ?

  26. The Law of Independent Assortment or Why Mendel was so Lucky • Mendel's next step was to cross plants that bred true for each of TWO traits, e.g.... • seed shape (Round or wrinkled, Round dominant; R/r) • seed color (Yellow or green, yellow dominant; Y/y) • Parental cross: RRYY x rryy • F1 are Round, Yellow (RrYy) • Self F1s... P X F1

  27. Male F1 parent = RrYy The "Dihybrid Cross" - Dependent Assortment • Hypothesis: Loci ("Traits" to Mendel) assort together ("dependently") • If a gamete has an R allele, it also has a Y allele (recall P generation was RRYY, rryy) • If a gamete has an r allele it also has a y allele • What are the expected frequencies of F2 phenotypes? RY ry RY Female F1 parent = RrYy ry

  28. Male F1 parent = RrYy RY ry RRYY RrYy RY Female F1 parent = RrYy rRyY rryy ry The "Dihybrid Cross" - Dependent Assortment • Hypothesis: Loci assort together ("dependently") • If a gamete has an R allele, it also has a Y allele (recall parents were RRYY, rryy) • If a gamete has an r allele it also has a y allele • What are the expected frequencies of F2 phenotypes?

  29. Male F1 parent = RrYy Female F1 parent = RrYy The "Dihybrid Cross" - Dependent Assortment • Predict 3/4 round, yellow, 1/4 wrinkled, green • NOT WHAT MENDEL OBSERVED! RY ry RRYY RrYy RY rRYy rryy ry

  30. RRYY RRYy RrYY RrYy RRYy RRyy RrYy Rryy RrYY RrYy rrYY rrYy RrYY Rryy rrYy rryy The "Dihybrid Cross" - Independent Assortment Male F1 parent = RrYy • Four combinations of alleles in gametes • All are equally likely • Expect traits in 9:3:3:1 ratio • THIS IS WHAT MENDEL OBSERVED RY Ry rY ry RY Ry Female F1 parent = RrYy rY ry

  31. Mendel's Laws • The Law of Segregation - ONE LOCUS • If the locus is heterozygous, half the gametes get one allele, half the gametes get the other allele • The Law of Independent Assortment - MULTIPLE LOCI • Alleles at each locus segregate independently of alleles at other loci • (When is this not true? or Why was Mendel so lucky?)

  32. Introduction to Probability Theory • Independent Events - if the outcome of one event does not depend on the outcome of some other event • e.g., rolls of a die, flips of a coin, segregation of loci on different chromosomes • The probability of BOTH of two events happening is the product of the probability of each event happening independently. • Formally, Pr(A and B) = Pr(A) x Pr(B) • e.g., Pr(two heads on two flips) = Pr(1st flip heads) x Pr(2nd flip heads)

  33. Introduction to Probability Theory • Probability of EITHER of two events happening is the sum of the probability of each event happening independently • Formally, Pr(A or B) = Pr(A) + Pr(B) • e.g., Pr(one head on two flips) = Pr(head,tail or tail,head) Pr(1st flip tails)*Pr(2nd flip heads) = (1/2)(1/2) =1/4 Pr(1st flip heads)*Pr(2nd flip tails) = 1/4 • 1/4 + 1/4 = ½ • Pr(1-locus heterozygote) = Pr(Aa) + Pr(aA) = ¼ + ¼ = ½

  34. For tomorrow... • Mendelian Genetics, continued • Pedigree analysis • Read the rest of Ch. 14

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