1 / 28

Chapter 31

Chapter 31. Nuclear Physics and Radioactivity. 1. Nuclear Structure. Proton - positive charge - mass 1.673 x 10 -27 kg ≈ 1 u b) Neutron - discovered by Chadwick (student of Rutherford) - hypothesized to account for mass of atom - discovered with scattering experiments - zero charge

sarah-todd
Télécharger la présentation

Chapter 31

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Chapter 31 Nuclear Physics and Radioactivity

  2. 1. Nuclear Structure • Proton - positive charge - mass 1.673 x 10-27 kg ≈ 1 u b) Neutron - discovered by Chadwick (student of Rutherford) - hypothesized to account for mass of atom - discovered with scattering experiments - zero charge - mass 1.675 x 10-27 kg ≈ 1 u - mass of neutron ≈ mass of proton + mass of electron - neutron can eject electron to form proton, but it’s not a proton and an electron

  3. c) Nucleon - constituent of nucleus (neutron or proton) d) Nomenclature A - number of nucleons (atomic mass number) Z - number of protons N - number of neutrons A = Z + N Symbol for nucleus of chemical element X:

  4. Examples: Since Z determines the element (X), only AX is needed.

  5. e) Atomic mass unit, u Define: Mass of 12C = 12 u Then, 1 u = 1.66 x 10-27 kg = 931.5 MeV/c2 mp = 1.00727 u mn = 1.008665 u In chemistry and biology, 1 dalton (Da) = 1 u

  6. e.g. 35Cl, 37Cl (65%, 35%), 12C, 13C, 14C (99%, 1%, 0.01%) f) Isotopes; nuclei with the same Z, different N g) Nuclear size and density Close-packed - constant density - Volume proportional to atomic number (A) - Since V = 4/3 πr3, A prop. to r3 - r prop. A1/3 - r ≈ (1.2 x 10-15 m) A1/3 = 1.2 fm A1/3 - density of neutron star = 100 million tonne/cm3

  7. 2. Nuclear force and stability • Strong nuclear force • one of the fundamental forces • holds protons together in spite of Coulomb repulsion • short range: ~ fm (zero for longer range) • only adjacent nucleons interact • acts equally between n-p, n-n, p-p

  8. - Pauli exclusion principle: N=Z gives maximum stability considering only nuclear force c) Coulomb repulsion b) Symmetry • long range; all protons interact (only adjacent nucleons feel nuclear force) • - repulsion increases with size -- neutron excess needed for stability • - above Z = 83 (Bi) stability not possible; larger elements decay emitting radioactivity

  9. 3. Mass defect and binding energy a) Binding energy energy required to separate constituents of nucleus

  10. From special relativity, adding energy increases mass: b) Mass defect

  11. Example: 4He (alpha particle) Compare ionization potential for H atom: 13.6 eV

  12. Masses usually tabulated for neutral atoms (including atomic electrons) - Can use atomic masses if electrons balance: c) Atomic electrons

  13. - determines stability - for 4He, BE = 28 MeV so BE/nucleon = 7 MeV d) Binding energy per nucleon increase in nearest neighbors increase in Coulomb repulsion dominates

  14. Energy released For a given number of nucleons, - if BE/nucleon increases - mass defect increases - total mass decreases - energy released Fusion Fission

  15. Fusion: Potential energy diagram for nucleons: fusion releases energy Energy (high temperature in the sun) required to push nuclei together against the Coulomb force.

  16. Fission: Potential energy diagram for two halves of a large nucleus: fission releases energy May occur spontaneously, or be induced by neutron bombardment

  17. 4. Radioactivity • spontaneous decay of nucleus • releases energy to achieve higher BE/nucleon • mass of parent > mass of products

  18. - ejection of 4He nucleus - transmutation: element changes a) - decay - Energy released (KE of , daughter, energy of photon) Use atomic masses for P, D, 4He (electrons balance): -decay For 238U, 234Th, 4He, E = 4.3 MeV

  19. - ejection of electron - governed by weak nuclear force - transmutation b)  - decay - Energy released, as KE of electron Use atomic masses for P, D, and add one electron mass: - decay For 234Th and 234Pa, E = 0.27 MeV

  20. Other modes of beta decay - ejection of positron - electron capture

  21. - emission of a photon - no transmutation - accompanies  - decay, fission, neutron decay c)  - decay

  22. - sequential decays to an eventual stable nucleus • 4 separate series (A can only change by 4) d) Decay series 238U -> 206Pb 235U -> 207Pb 232Th -> 208Pb 237Np -> 209Bi (not obs’d)

  23. postulated by Pauli in 1930 to account for missing energy in -decay e) Neutrino,  • observed in 1956 • mass ~ zero (< ~ eV) (standard model predicts non-zero mass) • could account for missing mass in universe • zero charge • interacts only by weak nuclear force (difficult to detect)

  24. 5. Radioactive decay rate; activity Activity is the number of decays per unit time, or a) Activity where N represents the number of nucleii present. For a random process, the activity is proportional to N:  is the decay constant This gives (by integration) where N0 is the number of nuclei at t = 0. Units: 1 Bq (becquerel) = 1 decay/s 1 Ci (curie) = 3.7 x 1010Bq (activity of 1 g radium)

  25. Exponential decay: For a given time interval, the fractional decrease in N is always the same: b) Half-life Define half-life as the time for activity to reduce by 1/2:

  26. Using the exponential can be expressed so

  27. 6. Radioactive dating - based on the reaction: T1/2 = 5730 years a) Carbon dating - 14C/12C ratio constant in atmosphere due to cosmic rays - living organisms ingest atmospheric carbon; dead matter doesn’t - ratio of 14C/12C in matter gives time since death Equilibrium ratio: 1/8.3 x 1011 ==> 1 g C contains 6 x 1010 atoms of 14C ==> Activity of 1g C (at eq’m) = 0.23 Bq = A0 ==> Activity of 1g C (time t after death) = A= A0e-t

  28. b) Dating ancient rocks Age equation:

More Related