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Section 10.2.2 Euler's Method

Section 10.2.2 Euler's Method. Diff. Equ. February 24, 2009 Berkley High School. Consider a Differential Equation: y'=x+y. We would like an approximation of the curve of y(x) that goes through y(0)=2. What is the slope at y(0)=2? slope is 0+2=2

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Section 10.2.2 Euler's Method

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  1. Section 10.2.2Euler's Method Diff. Equ. February 24, 2009 Berkley High School

  2. Consider a Differential Equation: y'=x+y • We would like an approximation of the curve of y(x) that goes through y(0)=2. • What is the slope at y(0)=2? • slope is 0+2=2 • Let ∆x = 1. What is our best guess as to the value of y(1)? • 2+2=4. We think that a point on that curve is approximately y(1)=4

  3. Consider a Differential Equation: y'=x+y • We would like an approximation of the curve of y(x) that goes through y(1)=4. • What is the slope at y(1)=4? • slope is 1+4=5 • Let ∆x = 1. What is our best guess as to the value of y(2)? • 4+5=9. We think that a point on that curve is approximately y(2)=9

  4. Consider a Differential Equation: y'=x+y • We would like an approximation of the curve of y(x) that goes through y(2)=9. • What is the slope at y(2)=9? • slope is 2+9=11 • Let ∆x = 1. What is our best guess as to the value of y(3)? • 9+11=20. We think that a point on that curve is approximately y(3)=20

  5. Consider a Differential Equation: y'=x+y • We would like an approximation of the curve of y(x) that goes through y(0)=2. • What is the slope at y(0)=2? • slope is 0+2=2 • Let ∆x = .5. What is our best guess as to the value of y(.5)? • 2+.5*2=3. We think that a point on that curve is approximately y(.5)=3

  6. Consider a Differential Equation: y'=x+y • We would like an approximation of the curve of y(x) that goes through y(.5)=3. • What is the slope at y(.5)=3? • slope is .5+3=3.5 • Let ∆x = .5. What is our best guess as to the value of y(1)? • 3+.5*3.5=4.75. We think that a point on that curve is approximately y(1)=4.75

  7. Consider a Differential Equation: y'=x+y • We would like an approximation of the curve of y(x) that goes through y(1)=4.75. • What is the slope at y(1)=4.75? • slope is 1+4.75=5.75 • Let ∆x = .5. What is our best guess as to the value of y(1.5)? • 4.75+.5*5.75=7.625. We think that a point on that curve is approximately y(1.5)=7.625

  8. Exercises • Section 10.2: 19-24 all

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