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8.3

8.3

8.3. 8255A ??????. ??? ????????? ??????????? ???????? ??? ??????? 8255A ?? 8255A ??????? ?? 8255A ???? ?? 8255A ? ???? ?? 8255A ?????. ??? ????????? ??????????? ????????. ???????????. ?? ????????????????????? ??????? : ?????????. 0. 1. D0 D1 D2 D3 D4 D5 D6 D7. D0

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901 views • 72 slides
GEOS 459/559 - Thermochronology

GEOS 459/559 - Thermochronology

GEOS 459/559 - Thermochronology. Today: Why take this class? Intro to nuclear stability and decay . Who needs this?. Tectonicists and petrologists working with multi-Ma rocks Some 85% of the papers published in the journal Tectonics contain some quantitative geochron / thermochron data;

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511 views • 28 slides
n o l m j k h i

n o l m j k h i

Pre-Processing What is the best amount of amortized preprocessing? E.g., for the 16x16 spatial dataset at right? Note that there is no count measurement associated with each point and similarity is simple spatial closeness.

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261 views • 16 slides
7.3 Divide-and-Conquer Algorithms and Recurrence Relations

7.3 Divide-and-Conquer Algorithms and Recurrence Relations

7.3 Divide-and-Conquer Algorithms and Recurrence Relations. If f(n) represents the number of operations required to solve the problem of size n, it follow that f satisfies the recurrence relation f(n) = af (n/b) + g(n)

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544 views • 13 slides
Binary-to-BCD Converter

Binary-to-BCD Converter

Binary-to-BCD Converter. Lecture L6.2 Section 6.5 pp. 101-106. Shift and Add-3 Algorithm. S1. Shift the binary number left one bit. 22. If 8 shifts have taken place, the BCD number is in the Hundreds , Tens , and Units column.

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152 views • 13 slides
Levenshtein-distance-based post-processing shared task spotlight

Levenshtein-distance-based post-processing shared task spotlight

Levenshtein-distance-based post-processing shared task spotlight. Antal van den Bosch ILK / CL and AI, Tilburg University Ninth Conference on Computational Natural Language Learning (CoNLL-2005) Ann Arbor, MI, June 29-30, 2005. Global models ? Post-processing. Many systems:

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225 views • 9 slides
Arithmetic Circuits II

Arithmetic Circuits II

Arithmetic Circuits II. Multiplier. Given the multiplicand, B = {B 1 B 0 } and the multiplier A = {A 1 A 0 } Then we multiply by doing single-bit multiplications and shifts. AND computes A 0 B 0. A. 0. B. B. 1. 0. A. 1. B. B. 1. 0.

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91 views • 8 slides

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