'Ab 5' diaporamas de présentation

Molecular Geometry and Bonding Theories

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Molecular Geometry and Bonding Theories

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CSCI 3130: Automata theory and formal languages

Fall 2011. The Chinese University of Hong Kong. CSCI 3130: Automata theory and formal languages. LR(0) grammars. Andrej Bogdanov http://www.cse.cuhk.edu.hk/~andrejb/csc3130. Parsing computer programs. First the javac compiler does a lexical analysis :. if (n == 0) { return x; }.

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O. M. x. ????. ?? Ox ??? M ?????????????. x. ?? Ox ??? M ?????????? x ???. y. A. y. x. x. O. ????????? M ???????. ( x , y ). ????????? M ????????? (x ? y) ???. M. z. O. y. x. ????? M ?????????????. z. ? x ? y ? z ?. y. x.

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CSC 3130: Automata theory and formal languages

Fall 2009. The Chinese University of Hong Kong. CSC 3130: Automata theory and formal languages. Parsers for programming languages. Andrej Bogdanov http://www.cse.cuhk.edu.hk/~andrejb/csc3130. CFG of the java programming language. Identifier: IDENTIFIER QualifiedIdentifier:

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5-Minute Check 1

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ESSENTIAL OBJECTIVE Use the Pythagorean Theorem and the Distance Formula.

ESSENTIAL OBJECTIVE Use the Pythagorean Theorem and the Distance Formula. Right Triangle. The sides that form the right angle are called the legs . The side opposite the right angle is called the hypotenuse. The Pythagorean Theorem.

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Match the expressions

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The Binomial Theorem

The Binomial Theorem. Patterns in Binomial Expansions. By studying the expanded form of each binomial expression, we are able to discover the following patterns in the resulting polynomials. 1. The first term is a n . The exponent on a decreases by 1 in each successive term.

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?????. ??????. o. ? AB ?? = 5. C: (0 ,5 ). B: (3 ,5). ??????. A: (3 ,0). o. ? AB ?? = 5 BC ?? = ?. C: (0 ,5 ). B: (3 ,5). ??????. A: (3 ,0). o. ? AB ?? = 5 BC ?? = ? OC ?? = ?. C: (0 ,5 ). B: (3 ,5). ??????. A: (3 ,0). o. ??? ABCO ?? = ?. C: (3 ,5).

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CHAPTER 9

CHAPTER 9. AP/HONORS CHEMISTRY. MOLECULAR GEOMETRY. VSEPR - valence-shell electron pair repulsion IDEAL GEOMETRIES Type geometry bond angle AB 2 (2 e- pairs) Linear 180 o example on board

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Geometry

Geometry. Unit V Section 6.3 Part II: Quadrilaterals in the Coordinate Plane. Equal. Opposite reciprocals. 7/4. -7/4. 2/5. -4. -4. 2/5. -7/4. 7/4. Parallelogram, rhombus. parallelogram. mBD = undef. Distance of BD= 14. Distance of AB= 4.12. Distance of BD= 6.32. mAC = 0.

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Geometry

Geometry. Unit V Section 6.3 Part II: Quadrilaterals in the Coordinate Plane. Equal. Opposite reciprocals. 7/4. -7/4. 2/5. -4. -4. 2/5. -7/4. 7/4. Parallelogram, rhombus. parallelogram. mBD = undef. Distance of BD= 14. Distance of AB= 4.12. Distance of BD= 6.32. mAC = 0.

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??????:. ?????????. ??????; 1:??: (1). ( x+2)(x+3); (2). (x+2)(x-3); (3). (x-2)(x-3); (4)(x+a)(x+b);. ???:. ( x+a)(a+b). ?????:. a ? b ????????. x x. 6 -3. ?:??=. ( x + 6). ( x -3 ). (1). ???? ???;. (2). ???? ???;

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