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Unit 5 Topic1 The Mole

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In the same manner g AlCl 3 = g Al ( FW AlCl 3 /at wt Al) g FeCl 3 + g AlCl 3 = 5.95

What weight of sulfur (FW = 32.064) ore which should be taken so that the weight of BaSO 4 (FW = 233.40) precipitate will be equal to half of the percentage sulfur in the sample. Solution S D BaSO 4 mmol S = mmol BaSO 4 mg S/at wt S = mg BaSO 4 /FW BaSO 4

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welcome

welcome. Introduction. Teacher Md.Alamgir kabir Ass-Teacher Henchi B.B.High School. Lesson English 1st Paper Class-Nine Time-40 (mi). Learning outcomes. Know meaning of new Vocabularies. Ask and answer questions . Take part in debates on given topics.

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Chapter 6 Gases

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12.3 Limiting Reagent and Percent Yield

12.3 Limiting Reagent and Percent Yield. By: Michelle Alice Ganian. Limiting Reagent. In a chemical reaction, an insufficient quantity of any of the reactants will limit the amount of product that is formed.

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