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Page 88, Dihybrid Problems #2

Page 88, Dihybrid Problems #2.

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Page 88, Dihybrid Problems #2

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  1. Page 88, Dihybrid Problems #2 In rabbits, black coat color is due to a dominant gene B, brown coat color is due to a recessive gene b. Short hair is due to a dominant gene S, long hair to its recessive allele s. In a cross between 2 heterozygous black, short haired rabbits, what would be the phenotypic ratio of the offspring?

  2. B – black coat b – brown coat S – short hair s – long hair Cross between 2 heterozygous black, short haired rabbits BbSs x BbSs B B b b S S s s BS Bs bS bs

  3. #1 Results bS bs BS Bs BS BbSs BBSS BBSs BbSS BBSs BBss BbSs Bbss Bs bS BbSS BbSs bbSS bbSs BbSs Bbss bbSs bbss bs

  4. B – black; b – brown; S – short; s - long BS Bs bS bs Black (B), short (S) Black (B), long (s) Brown (b), short (S) Brown (b), long (s) BbSs BS BBSS BBSs BbSS Bs BBSs BBss BbSs Bbss bS BbSS BbSs bbSS bbSs bs BbSs Bbss bbss bbSs 9 : 3 : 3 : 1

  5. Page 88, Dihybrid Problems #2 In horses, black color is dependent upon a dominant gene B, and chestnut upon its recessive allele b. The trotting gait is due to a dominant gene T and the pacing gait to its recessive allele t. if a homozygous black pacer is mated to a homozygous chestnut trotter, what will the genotype and phenotype of the F1 generation be?

  6. B – black b – chestnut T - trotting t – pacing Homozygous x Homozygous black pacer chestnut trotter BBtt x bbTT Bt Bt Bt Bt bT bT bT bT

  7. B – black; b – chestnut; T – trotting; t - pacing Bt Bt Bt Bt bT BbTt BbTt BbTt BbTt All offspring BbTt — Black Trotters bT BbTt BbTt BbTt BbTt bT BbTt BbTt BbTt BbTt bT BbTt BbTt BbTt BbTt

  8. Page 88, Dihybrid Problems #3 If two F1 individuals from #3 were mated, what would be the phenotypic ratio of the offspring? BbTt x BbTt BT Bt bT bt BT Bt bT bt

  9. B – black; b – chestnut; T – trotting; t - pacing BT Bt bT bt BT Bt bT bt BBTT BBTt BbTT BbTt 9:3:3:1 BBTt BBtt BbTt Bbtt BbTT BbTt bbTT bbTt BbTt Bbtt bbTt bbtt

  10. Page 88, Dihybrid Problems #4 An organisms has the genotype AABb. It is crossed with an individual with the genotype Aabb. What type of gametes can be produced by these two individuals? AABb x Aabb AB Ab AB Ab Ab Ab ab ab

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