1 / 5

Young's Double-Slit PHY 213 and PHY 201

Young's Double-Slit PHY 213 and PHY 201. Important points to consider: The value of m is determined by which points you choose, to find "y". If you solve for  using the distance (y) from the center maximum fringe to the first maximum fringe, then m = 1. screen. A. m =1. y. . d. m = 0.

sian
Télécharger la présentation

Young's Double-Slit PHY 213 and PHY 201

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Young's Double-SlitPHY 213 and PHY 201 Important points to consider: • The value of m is determined by which points you choose, to find "y". If you solve for  using the distance (y) from the center maximum fringe to the first maximum fringe, then m = 1.

  2. screen A m =1 y  d m = 0 B Path difference = d sin  L The Problem: In a certain Young’s double-slit experiment for which L = 1.00 m and d = 0.10 cm, the bright fringes are 0.050 cm apart. What wavelength of light is being used?

  3. A  d B opposite “Bright fringes” are points on the screen which represent areas of maximum constructive interference – bright spots for light and loud spots for sound. In this example, two bright fringes are located at m = 1 and m = 0. At m = 0, the path difference for waves leaving points A and B equals 0. At m = 1, this path difference equals one wavelength or m. Upon solving the triangle below, this path difference becomes (d sin ).

  4. Now, because this opposite side is the path difference, m; If we choose the point, m = 1, and we know the value of “d”, all that is needed is . m = 1 y  L m = 0 The bright fringes (m = 0, m = 1) are 0.050 cm apart.

More Related