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NCERT Online Maths Solutions For Class 10th Statistics

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NCERT Online Maths Solutions For Class 10th Statistics

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  1. NCERT Online Maths Solutions For Class 10th Statistics

  2. NCERT Online Maths Solutions For Class 10th Statistics Online Maths Solutions For Class 10th Statistics : In my last article for 10th Class Maths, I have discussed Mean and the defined ways to find Mean. In this article, we will discuss Median, Mode and CBSE NCERT Online Solutions. Mode Let’s define mode, the value which has the maximum frequency, or the maximum observation is known as Mode. It can also be defined as the most occurring value is known as Mode. Mode=I + (fi – fo) *h (2fi–fo–f2)

  3. NCERT Online Maths Solutions For Class 10th Statistics Where l = lower limit of the modal class, h = size of the class interval f1 = frequency of the mode class f0 = frequency of preceding mode class f2 = frequency of succeeding mode class. So, we will explain few ‘CBSE NCERT Online Solutions’ to explain the above formula. Let’s discuss Q2 of exercise 14.2 Q2-The following data give the information on the observed lifetimes (in hours) of 225 Electrical components:

  4. NCERT Online Maths Solutions For Class 10th Statistics

  5. NCERT Online Maths Solutions For Class 10th Statistics Determine the modal lifetimes of the components. Solution- The class 60-80 has the highest frequency hence l=60 h=20 fi=61 fo=52 f2=38 Mode=l + (fi-fo/ 2f1-fo-f2)*h =60 + (61-52 /2*61-52-38)*20 =60 + 9/32 *20 =60+5.625 = 65.625 The modal lifetimes of the components =65.625.

  6. NCERT Online Maths Solutions For Class 10th Statistics Median In a grouped data, we may not be able to find the middle observation by looking at the cumulative frequencies as the middle observation will be some value in a class interval. We will find a value within the class that will divide the entire observation set into two equal parts. To find the observation class, we should calculate the cumulative frequencies of all the classes and n/2. Now, we locate the class whose cumulative frequency is greater than n/2. This is called the median class. After this, we will find Median- Median= l + (n/2-cf) *h f

  7. NCERT Online Maths Solutions For Class 10th Statistics Where l = lower limit of the median class taken n = number of observations in question cf = cumulative frequency preceding median class, f = frequency of median class, h = class size considered Let’s discuss one CBSE NCERT solution to understand the same. Q1 of exercise 14.3. Q1- The following frequency distribution gives the monthly consumption of electricity 68 consumers of a locality. Find the mean, median and mode of the below data and compare them.

  8. NCERT Online Maths Solutions For Class 10th Statistics

  9. NCERT Online Maths Solutions For Class 10th Statistics Solution: - We will discuss the median calculation only. We will calculate the cumulative frequency:-

  10. NCERT Online Maths Solutions For Class 10th Statistics N=68 n/2=34 Median=l +{(n/2-cf)/f}*h = 125{(34-22)/20}*20 = 125+12=137 So, now we have discussed all the three measures of central tendency as per Class 10 Maths syllabus. For more information ‘Online Maths Solutions For Class 10th Statistics’, CBSE Exams,sample papers and CBSENCERT Solutions Class 10, Click here For animated Class 10 Maths Video lectures, the student can also visit Takshila Learning Or call us: 8800999280/8800999284/011-45639131.

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