1 / 9

Neutralization of an acid or base.

Neutralization of an acid or base. Mixing acids and bases. ~creates water H 3 O + + OH -  2 H 2 O this is called neutralizing the solution a neutralized solution is no longer dangerous. The point where neutralization is complete is called the equivalence point. Salts.

teresa
Télécharger la présentation

Neutralization of an acid or base.

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Neutralization of an acid or base.

  2. Mixing acids and bases • ~creates water • H3O+ + OH- 2 H2O • this is called neutralizing the solution • a neutralized solution is no longer dangerous. • The point where neutralization is complete is called the equivalence point

  3. Salts • ~the byproduct of an acid and a base. • NaOH + HCl  H2O + NaCl • (base) (acid) (water) (salt) • there are several more than just table salt. • HNO3 + NH4OH  H2O + NH4NO3 • Acid Base water salt

  4. Gases can be created • this depends on the reactants (not all will) • sodium bicarbonate (baking soda) will pretty much always release a gas • NaHCO3 + H2SO4H2O + NaHSO4 +CO2 Salt Gas

  5. Titration • ~mixing an acid and base perfectly to make a neutral solution. • You normally need some kind of indicator for this. • Phenolphthalein- when in solution turns red if basic and is clear if acidic. • You can also use a pH probe

  6. Graph of titration equivalence point pH Volume strong base added

  7. Using math • To neutralize a solution you will need to add an equal amount of H3O+ / OH- to what was already present. • so that • mol H3O+ = mol OH- • This is used if and only if you are at the equivalence point (completely neutral solution)!

  8. Problem • If 94 mL of 4.0 M NaOH neutralizes 6.0 L of an unknown strong acid, what was the H3O+concentration of the unknown? • 4 M NaOH x .094 L = .376 mol NaOH • .376 mol H3O+/ 6.0 L = .063 M H3O+

  9. Another problem • If 127 mL of 2.0 M NaOH neutralizes 4.1 L of an unknown acid, what is the initial concentration of the acid? • 2.0M(.127 L) = .254 mol NaOH • =.254 mol OH- = .254 mol H3O+ • 4.1 L • =.062 M

More Related