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F=BIL

F=BIL. Or is it…. F=qvB. Also Determine the direction of the Force! . V. B. Positive Charge is moving. Use: F=qvB Force is going:. V. B. Negative Charge is moving. Use: F=qvB Force is going: Coming out of the page!. B. I. Use: F=BiL Force is going:. F = 1.5x10 -12 N.

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F=BIL

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  1. F=BIL Or is it….. F=qvB Also Determine the direction of the Force! 

  2. V B Positive Charge is moving

  3. Use: F=qvB Force is going:

  4. V B Negative Charge is moving

  5. Use: F=qvB Force is going: Coming out of the page!

  6. B I

  7. Use: F=BiL Force is going:

  8. F = 1.5x10-12 N V = 2.0x107 m/s Electron B = ?

  9. Use: F=qvB 1.5 x 10-12= (1.6 x 10-19C) x (2.0x107 m/s) x B B= .46875 T Force is going:

  10. B = .15 T Electron V = 1.5x106 m/s F = ?

  11. You would break your hand trying this one so the charge will not feel any force

  12. What is the acceleration of the proton? Mass of a proton is = 1.67262158 × 10-27 kilograms B = .75 T Proton V = 5.8x106m/s

  13. Use: F=qvB F=ma ma=qvB (1.67262158 × 10-27 kg)x a = (1.6 x 10-19C) x (5.8x106m/s) x .75 T a = 4.167 x 1014 m/s/s Force is going:

  14. 1. What is the acceleration of the electron? B = .75 T 2. What is the radius of curvature? Hint: ac = v2/r Electron V = 4.5x107m/s

  15. Use: F=qvB F=mv2/r mv2/r=qvB (9.11 × 10-31 kg)(4.5x107m/s)2/r= (1.6 x 10-19C) x (4.5x107m/s) x .75 T r = 3.4 x 10-4 m Force is going:

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