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Entry Task: May 15 th -16 th Block #1

Entry Task: May 15 th -16 th Block #1. Question: How much of a 5.0M solution of carbonic acid is needed to neutralize 60 mls of a 3.5M sodium hydroxide? You have 5 minutes!. Agenda:. Collect ANY Acetic Acid labs Discuss titration ws . In-class Ch. 19 (Acid-Base) Review sheet

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Entry Task: May 15 th -16 th Block #1

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  1. Entry Task: May 15th -16th Block #1 Question: How much of a 5.0M solution of carbonic acid is needed to neutralize 60 mls of a 3.5M sodium hydroxide? You have 5 minutes!

  2. Agenda: • Collect ANY Acetic Acid labs • Discuss titration ws. • In-class Ch. 19 (Acid-Base) Review sheet • What you don’t finish becomes homework!

  3. 1. Give the word equation for the neutralization reaction of an acid and a base. 2. Complete these equations: HCl + LiOH HC2H3O2+ Mg(OH)2 Acid + base  salt and water LiCl + H2O 2 Mg(C2H3O2)2 + H2O 2

  4. 3. A _______________ is a laboratory method used to determine the concentration of an acid or a _______________ in solution by performing a _______________ reaction with a standard solution. 4. At the ______________ of the titration, the indicator changes color, this indicates neutralization. Once neutralized, moles of _______________ and moles of _______________ are equal. titration base neutralization Equivalence pt acid base

  5. 5. In a titration of hydrochloric acid with sodium hydroxide, 100.0 mL of the base was required to neutralize 20.0 mL of 5.0 M hydrochloric acid. What is the molarity of the sodium hydroxide? HCl + NaOH  NaCl + H2O (5.0M)(20.0ml) = (XM)(100 ml) 100= x 100 X= 1.0 M of NaOH

  6. 6. In a titration of phosphoric acid with potassium hydroxide, 60.0 mL of 0.020 M potassium hydroxide was needed to neutralize 15.0 mL of phosphoric acid. What is the molarity of the acid? H3PO4 + KOH  K3PO4 + H2O 3 3 3 (X M)(15.0ml) = (0.020M)(60 ml) 1.2= x 45 X= 0.027 M of acid

  7. 7. If 10.0 mL of 0.300 M calcium hydroxide are required to neutralize 30.0 mL of gastric juice (hydrochloric acid), what is the molarity of the gastric juice? HCl + Ca(OH)2  CaCl2 + H2O 2 2 (X M)(30.0ml) = (0.300M)(10.0 ml) 2 6= x 30 X= 0.2 M of acid

  8. 8. In a titration 12.5 mL of 0.200 M hydroiodic is required to neutralize 10.0 mL of strontium hydroxide. Calculate the concentration of the acid ? HI+ Sr(OH)2  SrI2 + H2O 2 2 (0.200 M)(12.5ml) = (XM)(10.0 ml) 2 2.5= x 20 X= 0.125 M of base

  9. 9. How many mL’s of 0.22 M cesium hydroxide solution is needed to neutralize 26.4 mL of 0.250 M hydrobromic acid? HBr+ CsOH  CsBr + H2O (0.250 M)(26.4ml) = (0.22M)(X ml) 6.6= x 0.22 X= 30 mls of base

  10. 10. What is the concentration of a 0.255L of calcium hydroxide solution is needed to neutralize 0.115 L of 0.200M hydrocyanic acid? HCN+ Ca(OH)2  Sr(CN)2 + H2O 2 2 (0.200 M)(0.115L) = (XM)(0.255 L) 2 0.023= x 0.51 X= 0.045 M of base

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