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Density Remediation

Density Remediation. 1. Find the density of a substance whose mass is 48,000 tons and volume is 0.000600 pL ?. 48,000 tons . 0.000600 pL ?. First, enter the givens into the density table. . 48,000 tons. D = . 0.000600 pL. 1. Find the density of a substance whose mass is

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Density Remediation

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  1. Density Remediation

  2. 1. Find the density of a substance whose mass is • 48,000 tons and volume is 0.000600 pL? 48,000 tons 0.000600 pL? First, enter the givens into the density table. 48,000 tons D = 0.000600 pL

  3. 1. Find the density of a substance whose mass is • 48,000 tons and volume is 0.000600 pL? Next, enter the units from the mass and volume into the left side of the density table. = ? tons 48,000 tons D = = ? pL 0.000600 pL No conversion is necessary.

  4. 1. Find the density of a substance whose mass is • 48,000 tons and volume is 0.000600 pL? Use the formula triangle to determine the correct formula. M ÷ D V x M V D =

  5. 1. Find the density of a substance whose mass is • 48,000 tons and volume is 0.000600 pL? Substitute the values into the equation. = ? tons 48,000 tons D = = ? pL 0.000600 pL D = M/V D = (48,000 tons) / (0.000600 pL)

  6. 1. Find the density of a substance whose mass is • 48,000 tons and volume is 0.000600 pL? Divide and round to the LEAST number of significant digits. = ? tons 48,000 tons D = = ? pL 0.000600 pL D = M/V D = (48,000 tons) / (0.000600 pL) D = 8.0 x 107tons/pL

  7. 2. Find the volume of a substance whose density is • 49.7 lbs/Tm3 and mass is 204,900 ng? 49.7 lbs/Tm3 204,900 ng? First, enter the givens into the density table. 204,900 ng 49.7 lbs D = 1 Tm3

  8. 2. Find the volume of a substance whose density is • 49.7 lbs/Tm3 and mass is 204,900 ng? Next, enter the units from the density into the right side of the density table. = ? lbs 49.7 lbs 204,900 ng D = 1 Tm3 = ? Tm3

  9. 2. Find the volume of a substance whose density is • 49.7 lbs/Tm3 and mass is 204,900 ng? If a conversion is necessary, complete it now. 204,900 ng = ? lbs 0.006921 lbs D = 1 Tm3 = ? Tm3

  10. 204,900 ng = ?? lbs Start with what you are looking for!! lbs 1 453.59 g Since lbs is an English unit and the given, ng, is a metric unit, Ms. Mullins must provide an English to metric conversion. Always look back at the instructions to find the conversions. Use: 1 lb = 453.59 g

  11. 204,900 ng = ?? lbs Bring the denominator unit up to the next numerator. 1 lb g 453.59 g

  12. 204,900 ng = ?? lbs Convert grams to nanograms. 1 lb g 453.59 g ng

  13. 204,900 ng = ?? lbs Since gis further left (so it is larger) than ng, ggets the one and nggets the ten. 1 lb 1 g 9 453.59 g 10 ng 1 2 3 4 5 6 7 8 9 T _ _ G _ _ M _ _ k h daunit d c m _ _ μ _ _ n_ _ p

  14. 204,900ng = ?? lbs Bring the denominator unit up to the next numerator. 1 lb 1 g 204,900 ng 453.59 g 109 ng When you have reached the given unit, ng, then insert the given numerical value.

  15. 204,900 ng = ?? lbs SOLVE!! 1 lb 1 g 204,900 ng = 4.517 x 107lbs 453.59 g 109 ng

  16. 2. Find the volume of a substance whose density is • 49.7 lbs/Tm3 and mass is 204,900 ng? Enter the answer from the dimensional analysis into the density table. = 4.517 x 107lbs 49.7 lbs 204,900 ng D = 1 Tm3 = ? Tm3

  17. 2. Find the volume of a substance whose density is • 49.7 lbs/Tm3 and mass is 204,900 ng? Use the formula triangle to determine the correct formula. M ÷ D V x M D V =

  18. 2. Find the volume of a substance whose density is • 49.7 lbs/Tm3 and mass is 204,900 ng? Substitute the values into the equation. 204,900 ng = 4.517 x 107lbs 49.7 lbs D = 1 Tm3 Tm3 V = M/D V = (4.517 x 107 lbs) / (49.7 lbs/Tm3)

  19. 2. Find the volume of a substance whose density is • 49.7 lbs/Tm3 and mass is 204,900 ng? Divide and round to the LEAST number of significant digits. 204,900 ng = 4.517 x 107lbs 49.7 lbs D = 1 Tm3 Tm3 V = M/D V = (4.517 x 107 lbs) / (49.7 lbs/Tm3) V = 2.24 x 105Tm3

  20. 3. Find the mass of a substance whose density is • 0.006921 lbs/mm3 and volume is 7.0835 x 107 mi3? 0.006921 lbs/Tm3 7.0835 x 107 mi3 ? First, enter the givens into the density table. 0.006921 lbs D = 1 Tm3 7.0835 x 107 mi3

  21. 3. Find the mass of a substance whose density is • 0.006921 lbs/Tm3 and volume is 7.0835 x 107 mi3? Next, enter the units from the density into the right side of the density table. = ? lbs 0.006921 lbs D = 1 Tm3 7.0835 x 107 mi3 = ? Tm3

  22. 3. Find the mass of a substance whose density is • 0.006921 lbs/Tm3 and volume is 7.0835 x 107 mi3? If a conversion is necessary, complete it now. = ? lbs 0.006921 lbs D = 1 Tm3 7.0835 x 107 mi3 = ? Tm3

  23. 7.0835 x 107 mi3 = ?? Tm3 Start with what you are looking for!! Tm3 Since Tm3 is a metric unit and the given, mi3, is an English unit, Ms. Mullins must provide an English to metric conversion. Always look back at the instructions to find the conversions. Use: 1 m = 1.0936 yd

  24. 7.0835 x 107 mi3 = ?? Tm3 Tm3 However, the conversion is not a cubic conversion so.... 1 m = 1.0936 yd (1 m)3 = (1.0936 yd)3 1 m3 = 1.3079 yd3

  25. 7.0835 x 107 mi3 = ?? Tm3 Tm3 In order to use the conversion, Tm3 must be converted to m3

  26. 7.0835 x 107 mi3 = ?? Tm3 Since Tm3 is further left (so it is larger) than m3, Tm3 gets the one and m3 gets the ten. 1 Tm3 10 m3 T _ _ G _ _ M _ _ k h daunit d c m _ _ μ _ _ n _ _ p

  27. 7.0835 x 107 mi3 = ?? Tm3 Either count by threes 1 Tm3 10 36 m3 3 6 9 12 15 18 21 24 27 30 33 36 T _ _ G _ _ M _ _ k h daunitd c m _ _ μ _ _ n _ _ p

  28. 7.0835 x 107 mi3 = ?? Tm3 Or count between units and multiply by three. 1 Tm3 10 36 m3 12 x 3 = 36 1 2 3 4 5 6 7 8 9 10 11 12 T _ _ G _ _ M _ _ k h daunitd c m _ _ μ _ _ n _ _ p

  29. 7.0835 x 107 mi3 = ?? Tm3 Bring the denominator unit up to the next numerator. 1 Tm3 m3 1036m3

  30. 7.0835 x 107 mi3 = ?? Tm3 Now use the English to metric cubic conversion. 1 Tm3 1 m3 1036 m3 1.3079 yd3 1 m = 1.0936 yd (1 m)3 = (1.0936 yd)3 1m3 = 1.3079 yd3

  31. 7.0835 x 107 mi3 = ?? Tm3 Bring the denominator unit up to the next numerator. 1 Tm3 1 m3 yd3 1036 m3 1.3079 yd3

  32. 7.0835 x 107 mi3 = ?? Tm3 Remember that you are working towards the given which is mi3. 1 Tm3 1 m3 1 yd3 1036 m3 1.3079 yd3 ft3 27 There isn’t a conversion between yards and miles, but there is between feet and miles, so first develop a conversion between yd3 and ft3. 1 yd = 3 ft (1 yd)3 = (3 ft)3 1 yd3= 27 ft3

  33. 7.0835 x 107 mi3 = ?? Tm3 Bring the denominator unit up to the next numerator. 1 Tm3 1 m3 1 yd3 ft3 1036 m3 1.3079 yd3 27 ft3

  34. 7.0835 x 107 mi3 = ?? Tm3 Remember that you are working towards the given which is mi3. 1 Tm3 1 m3 1 yd3 1.47 x 1011 ft3 1 mi3 1036 m3 1.3079 yd3 ft3 27 There is a conversion between feet and miles, so first develop a conversion between ft3 and mi3. 5280 ft = 1 mi (5280 ft)3 = (1 mi)3 1.47 x 1011 ft3= 1 mi3

  35. 7.0835 x 107 mi3 = ?? Tm3 Bring the denominator unit up to the next numerator. 1 Tm3 1 m3 1 yd3 1.47 x 1011 ft3 mi3 1036 m3 1.3079 yd3 27 ft3 1 mi3

  36. 7.0835 x 107mi3 = ?? Tm3 1 Tm3 1 m3 1 yd3 1.47 x 1011 ft3 7.0835 x 107 mi3 1036 m3 1.3079 yd3 27 ft3 1 mi3 When you have reached the given unit, mi3, then insert the given numerical value.

  37. 7.0835 x 107 mi3 = ?? Tm3 SOLVE!! 1 Tm3 1 m3 1 yd3 1.47 x 1011 ft3 7.0835 x 107 mi3 1036 m3 1.3079 yd3 27 ft3 1 mi3 = 2.9487 x 1019Tm3

  38. 3. Find the mass of a substance whose density is • 0.006921 lbs/Tm3 and volume is 7.0835 x 107 mi3? Enter the answer from the dimensional analysis into the density table. = ? lbs 0.006921 lbs D = 1 Tm3 7.0835 x 107 mi3 Tm3 = 2.9487 x 1019

  39. 3. Find the mass of a substance whose density is • 0.006921 lbs/Tm3 and volume is 7.0835 x 107 mi3? Use the formula triangle to determine the correct formula. M ÷ D V x M = DV

  40. 3. Find the mass of a substance whose density is • 0.006921 lbs/Tm3 and volume is 7.0835 x 107 mi3? Substitute the values into the equation. = ? lbs 0.006921 lbs D = 1 Tm3 7.0835 x 107 mi3 Tm3 = 2.9487 x 1019 M = DV M = (0.006921 lbs/Tm3) (2.9487 x 1019 Tm3)

  41. 3. Find the mass of a substance whose density is • 0.006921 lbs/Tm3 and volume is 7.0835 x 107 mi3? Multiply and round to the LEAST number of significant digits. = ? lbs 0.006921 lbs D = 1 Tm3 7.0835 x 107 mi3 Tm3 = 2.9487 x 1019 M = DV M = (0.006921 lbs/Tm3) (2.9487 x 1019 Tm3) M = (2.041 x 1021 lbs)

  42. Practice Problems: • 1. Find the mass of a substance whose density is • 3.544 x 106 dg/yd3and volume is 94,000 Mm3? • 2.Find the density of a substance whose mass is • 1.87 x 106 cg and volume is 234,567 dam3? • 3. Find the volume of a substance whose density is • 0.00807400 Gg/hm3and mass is 204,900 tons? • 4. Find the mass of a substance whose density is • 0.0007770 lbs/nL and volume is 4.7222 x 104 yd3? • 5. Find the density of a substance whose mass is • 4.8 x 1028 kg and volume is 640,800 TL? • 6. Find the volume of a substance whose density is • 3.04 x 1023g/m3and mass is 0.2030405 oz?

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