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Chapter 6 Gases

Chapter 6 Gases. 6.6 The Combined Gas Law. Combined Gas Law. The combined gas law uses Boyle’s Law, Charles’ Law, and Gay-Lussac’s Law (n is constant). P 1 V 1 = P 2 V 2 T 1 T 2. Combined Gas Law Calculation.

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Chapter 6 Gases

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  1. Chapter 6 Gases 6.6 The Combined Gas Law

  2. Combined Gas Law The combined gas law uses Boyle’s Law, Charles’ Law, and Gay-Lussac’s Law (n is constant). P1 V1= P2 V2 T1 T2

  3. Combined Gas Law Calculation A sample of helium gas has a volume of 0.180 L, a pressure of 0.800 atm and a temperature of 29°C. At what temperature (°C) will the helium have a volume of 90.0 mL and a pressure of 3.20 atm (n is constant)? 1. Set up Data Table Conditions 1 Conditions 2 P1 = 0.800 atm P2 = 3.20 atm V1 = 0.180 L (180 mL) V2 = 90.0 mL T1 = 29°C + 273 = 302 K T2 = ??

  4. Combined Gas Law Calculation (continued) 2. Solve for T2P1 V1 = P2 V2 T1 T2 T2 = T1 x P2 x V2 P1 V1 T2 = 302 K x 3.20 atm x 90.0 mL = 604 K 0.800 atm 180.0 mL T2 = 604 K - 273 = 331 °C

  5. Learning Check A gas has a volume of 675 mL at 35°C and 0.850 atm pressure. What is the volume(mL) of the gas at -95°C and a pressure of 802 mm Hg (n constant)?

  6. Solution Data Table Conditions 1 Conditions 2 T1 = 308 K T2 = -95°C + 273 = 178K V1 = 675 mL V2 = ??? P1 = 646 mm Hg P2 = 802 mm Hg Solve for V2 V2 = V1xP1 x T2 P2 T1 V2 = 675 mL x 646 mm Hg x 178K = 314 mL 802 mm Hg x 308K

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