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Gas Laws REVIEW GAME

Gas Laws REVIEW GAME. Question 1. A 4.3 liter tank of hydrogen is at a pressure of 6.2 atmospheres. What volume of hydrogen will be available if the hydrogen is used at pressure of 0.48 atmospheres? Boyle’s Law (4.3)(6.2) = 0.48V 2 V 2 = 56 L. Question 2.

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Gas Laws REVIEW GAME

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  1. Gas LawsREVIEW GAME

  2. Question 1 • A 4.3 liter tank of hydrogen is at a pressure of 6.2 atmospheres. What volume of hydrogen will be available if the hydrogen is used at pressure of 0.48 atmospheres? • Boyle’s Law • (4.3)(6.2) = 0.48V2 • V2 = 56 L

  3. Question 2 • What mass of oxygen gas must be placed in a container with a volume of 123.0L to produce a pressure of 1.87 atmospheres at 28.0°C? • Ideal Gas Law • 1.87(123) = n(0.0821)(301) • n = 9.3 mol x 32 = 298 g

  4. Question 3 • What is the pressure of 20.9 grams of neon gas at -19°C in a rigid container whose volume is 19.0 L? • Ideal Gas Law • 20.9 g Ne / 20 = 1.045 mol • P(19) = 1.045(0.0821)(254) • P = 1.2 atm

  5. Question 4 • A 4.45 L balloon at 14°C contains carbon dioxide gas. If the balloon is taken outside where the temperature is -22°C, what volume will the balloon occupy? • Charles Law • 4.45 / 287 = V2 / 251 • V2 = 3.9 L

  6. Question 5 • A gas occupies a volume of 0.65 L at 118.3 kPa and a temperature of 0.00°C. What volume will the gas occupy at 2.50 atm and 50.0°C? • Combined Gas Law • 118.3 kPa x (1 atm/101.325 kPa) = 1.17 atm • 1.17(0.65)/273 = 2.5V2/323 • V2 = 0.36 L

  7. Question 6 • A sample of gas occupies 25 mL at -142°C. What volume does the sample occupy at 65°C? • Charles • 25/131 = V2/338 • V2 = 65 mL

  8. Question 7 • When a container is filled with 6.000 grams of H2, 64.00 grams of O2, and 28.00 grams of N2, the pressure in the container is 5412 kPa. What is the partial pressure of O2? • Dalton’s Law • 6 g H2/2 = 3mol 64g O2/32 = 2mol 28 g N2/28 = 1mol • 3+2+1 = 6 total moles • PO2 = 2/6(5412) = 1804 kPa

  9. Question 7.5 • Magnesium reacts with hydrochloric acid • Mg + 2HCl  MgCl2 + H2 • How many grams of magnesium would I have to start with to make 3.5L of hydrogen gas at 130 kPa and 50. degrees celsius? • 130(3.5) = n (8.314)(323) • n = 0.17 mol H2 x 1/1 x 24.3 = 4.1 g

  10. Question 8 • What is the volume occupied by 71.0 grams of chlorine gas at STP? • Ideal Gas Law • 71 g Cl2 / 71 = 1 mol • 1V = 1(0.0821)(273) • V = 22.4 L

  11. Question 9 • A rigid container of O2 has a pressure of 185 kPa at a temperature of 458 K. What is the pressure at 283 K? • Gay Lussac’s Law • 185/458 = P2 / 283 • P2 = 114 kPa

  12. Question 10 • An unknown gas moves three times as fast as sulfur dioxide gas. What is the mass of the unknown gas? • Su = 3 mu = ? • Sso2 = 1 mso2 = 64 • 1/3 = Sqrt(m/64) • m = 7.1 g/mol

  13. Question 11 • How many moles of N2 are in a flask with a volume of 125 mL at a pressure of 2550 mm Hg and a temperature of 300.0 K? • Ideal Gas Law • 2550 mm Hg ( 1 atm / 760 mm Hg) = 3.36atm • 3.36 (0.125) = n (0.0821) ( 300) • 0.0171 mol N2

  14. Question 12 • The volume of a gas is 125 mL at 254 kPa pressure. What will the volume be when the pressure is reduced to 1.78 psi, assuming the temperature remains constant? • Boyle’s Law • 254 kPa ( 14.7psi / 101.325 kPa) = 36.85 psi • 36.85(125) = 1.78V • V = 2590 mL

  15. Question 13 • A mixture of gases at a total pressure of 95 kPa contains N2, CO2, and O2. The partial pressure of CO2 is 24 kPa and the partial pressure of the N2 is 48 kPa. What is the partial pressure of the O2? • Dalton’s Law • 95 = 24 + 48 + Po2 • Po2 = 23 kPa

  16. Question 14 • A gas, collected over water, has a measured pressure of 1.23 atm and has a volume of 590 mL at a temperature of 47°C. What volume will the dry gas occupy at 25°C and standard pressure? • Dalton and Combined • 1.23 atm (101.325 kPa / 1atm ) = 124.6 kPa • 124.6 kPa = Pgas + 10.62 • Pgas = 113.98 kPa • 113.98(590) / 320 = 101.325(V2) / 298 • 620 mL

  17. Question 15 • Nitrogen gas diffuses into an empty container at a rate of 254 m/s. At what velocity will carbon monoxide gas move at the same temperature? • Graham • VCO / 254 = Sqrt (28/28) • VCO = 254 m/s

  18. Question 16 • A gas initially is present, in a balloon, at 25°C under 1 atmosphere of pressure. The volume of the gas under these conditions is 2.5L. What will be the new volume of the gas if it is taken outside on a hot day, where the temperature is 85°C and the pressure is 1.08 atmospheres? • Combined • 1(2.5)/298 = 1.08V2/358 • V2 = 2.8 L

  19. Question 17 • 93.0 mL of O2 gas is collected over water at 0.930 atm and 10.0°C. What would be the volume of this dry gas at standard conditions? • Dalton and Combined • 0.930 atm x (101.325 kPa / 1atm) = 94.23 kPa • 94.23 kPa = Pgas + 1.2281 • Pgas = 93 kPa • 93(93)/283 = 101.325V2/273 • V2 = 82.3 mL

  20. Question 18 • If 9.0 moles of nitrogen gas will fill a balloon that is 2.0 L in volume at 293 K, what volume will 28 moles of nitrogen gas fill at the same temperature? • Avogadro’s Law • 2/9 = V2/ 28 • 6.2 L

  21. Question 19 • A large cylinder of He gas, such as that used to inflate balloons, has a volume of 25.0 L at 22°C and 5.6 atm. How many grams of He are in such a cylinder? • Ideal • 5.6(25) = n(0.0821)(295) • 5.78 mol x 4 = 23 g

  22. Question 20 • I begin with 460 mL of oxygen gas at a pressure of 740 mm Hg. How many liters of gas are present at standard pressure? • Boyle • 740(460) = 760(V2) • V2 = 450 mL

  23. Question 21 • Calculate the pressure of a gas whose temperature is increased from 15°C to 25°C and whose original pressure is 0.75 atm. • Gay Lussac • .75/288 = P2/298 • P2 = 0.78 atm

  24. Question 22 • A sample of gas at standard temperature and pressure is put into an expandable container. The original volume of the gas is 250 mL. What is the new volume if the gas is cooled to -15°C and the pressure is increased to 780 mm Hg? • Combined • (760)(250)/273 = 780V2/258 • V2 = 230 mL

  25. Question 23 • A balloon is filled with 150. mL of carbon dioxide gas at 900. mm Hg and 25.0°C. If the pressure is held constant, what will the new volume be if the temperature is raised to 75.0°C? • Charles • 150/298 = V2/348 • V2 = 175 mL

  26. Question 24 • Sulfur dioxide gas can move with a velocity of 150 m/s. How fast will carbon dioxide gas move at the same temperature? • Graham • V1/150 = Sqrt(64/44) • 180 m/s

  27. Question 25 • 6 moles of nitrogen gas is placed in a 3 L container. What volume will 18 moles of gas occupy under the same conditions • Avogadro • 3/6 = V2/18 • 9 L

  28. Question 26 • 40.0g of neon gas is put into a 500. mL container at 15.0°C. What is the pressure within the container in kPa? • Ideal • 40 g Ne / 20 = 2 mol • P(.5) = 2(8.314)(288) • 9580 kPa

  29. Question 27 • If a gas begins at a temperature of 27°C and a pressure of 150 kPa, what will the new pressure be when the temperature is raised to 50.°C? • Gay Lussac • 150/300 = P2/323 • 160 kPa

  30. Question 28 • Hydrogen gas moves with a velocity of 400. m/s at 25°C. What is the mass of a gas that moves at 250. m/s at the same temperature? • Graham • 400/250 = Sqrt(m2/2) • 5.12 g/mol

  31. Question 29 • Oxygen gas is collected over water at 18°C at a pressure of 800. mm Hg and a volume of 100. mL. What is the volume of the dry gas at STP? • Dalton and Combined • 800 mmHg x (101.325 kPa/760 mmHg) = 106.7 kPa • 106.7 = Pgas + 2.0644 • 104.6 kPa • 104.6(100)/291 = 101.325V2/273 • V2 = 97 mL

  32. Question 29 • 6Li + N2 2Li3N • I have 40.0 grams of lithium metal. How many liters of nitrogen gas will react with it at 230. kPa and 17.0 degrees celsius? • 40g/7 x 1/6 = 0.95 mol • 230(v) = 0.95(8.314)(290) • V = 9.95 L • I have 25.0 L of nitrogen gas at 1.34 atm and 80.0 degrees celsius. How many grams of Li3N can I make? • 1.34(25) = n (0.0821)(353) • n = 1.15 mol N2 x 2/1 x 35 = 80.5 g

  33. Question 30 • I have 80. grams of carbon monoxide gas, 55 grams of dinitrogen monoxide gas, and 100. grams of diphosphoruspentoxide gas. The total pressure of the mixture of gases is 1.67 atm. What is the partial pressure of each gas? • Dalton’s Law • 80 g CO / 28 = 2.86 mol • 55 g N2O / 44 = 1.25 mol • 100 g P2O5 / 142 = 0.70 mol • TOTAL MOLES = 4.81 moles • PCO = 2.86/4.81*(1.67) = 0.99 atm • PN2O = 1.25/4.81*(1.67) = 0.43 atm • PP2O5 = 0.70/4.81*(1.67) = 0.24 atm

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