1 likes | 27 Vues
This solution manual breaks down complex organic chemistry problems, making them easier to solve and understand. Perfect for students looking to enhance their comprehension and achieve higher grades. Contact us today to unlock these insights!
E N D
Email: smtb98@gmail.com Contact me in order to access the whole complete document. WhatsApp: https://wa.me/message/2H3BV2L5TTSUF1 smtb98@gmail.com Telegram: https://t.me/solumanu Okuyama & Maskill: Organic Chemistry smtb98@gmail.com Solutions to Problems, Chapter 1 1.1 (a) N (b) Na (c) Si (d) Cl 1.2 (a) 1 (b) 6 (c) 7 (d) 6 (e) 3 1.3 (a) 35Cl: 17 protons and 18 neutrons. 37Cl: 17 protons and 20 neutrons. (b) An approximate value for the relative atomic mass (atomic weight) of an element can be obtained from the weighted mean of the mass numbers (35 x 0.758 + 37 x 0.242 = 35.5). The accurate value is the weighted mean of the relative atomic masses of the individual isotopes (35.4527). 1.4 (a) covalent (b) covalent (c) covalent (d) ionic; O(–), Mg(+) (electronegativity difference = 2.1) (e) covalent 1.5 1.6 Bond dipoles cancel out in molecules (b) and (d), so they do not have overall dipoles. 1.7 .
Email: smtb98@gmail.com Contact me in order to access the whole complete document. WhatsApp: https://wa.me/message/2H3BV2L5TTSUF1 Telegram: https://t.me/solumanu Okuyama & Maskill: Organic Chemistry 1.8 1.9 1.10 1.11 1.12 . complete document is available on https://solumanu.com/ *** contact me if site not loaded
Email: smtb98@gmail.com Contact me in order to access the whole complete document. WhatsApp: https://wa.me/message/2H3BV2L5TTSUF1 smtb98@gmail.com Telegram: https://t.me/solumanu Okuyama & Maskill: Organic Chemistry (a) 109.5o (b) 109.5o (Note that the O has a lone pair.) (c) 120o at both Cs (d) 109.5o at the O and the N smtb98@gmail.com complete document is available on https://solumanu.com/ *** contact me if site not loaded Solutions to Problems, Chapter 2 2.1 2.2 2.3 2.4 2.5
Okuyama & Maskill: Organic Chemistry 2.6 2.7 (a) C5H8O (b) C7H12O (c) C7H12 (d) C4H9NO2 2.8 (a) (CH3)3CCH2CH=CHCOCH3 (b) (CH3)2C=CHN(CH3)CH2C(CH3)=CHCH2OH (c)C6H5OCH2CH=CHOCH3 (d) CH3CH2CH=CHCH2CO2CH2C≡CCH3 2.9 (a) the same compounds (b) constitutional isomers (c) stereoisomers (d) constitutional isomers (e) constitutional isomers (f) none of these 2.10 CH3CH2CH2CH2OH, (CH3)2CHCH2OH, CH3CH2CH(CH3)OH, (CH3)3COH, CH3CH2CH2OCH3, (CH3)2CHOCH3, CH3CH2OCH2CH3 2.11 (a) –CH3 < –NH2 (b) –CH2OH > –CH(CH3)2 complete document is available on https://solumanu.com/ *** contact me if site not loaded
Okuyama & Maskill: Organic Chemistry smtb98@gmail.com (c) –C(O)OCH3 > –C(O)N(CH3)2 (d) –Ph > –C(CH3)3 smtb98@gmail.com complete document is available on https://solumanu.com/ *** contact me if site not loaded (e) –C≡CH < –C≡N (f) –C≡N > –CH=NCH3 2.12 (a) Z (groups of higher priority: CH3 and OCH3) (b) E (groups of higher priority: HOCH2 and CN) (c) E (groups of higher priority: Ph and COOH) (d) E (groups of higher priority: CH2N(CH3)2 and OCH3) 2.13 2.14 Note that the central carbon is sp hybridized and the two bonds are orthogonal. The two planes where the lone pairs lie are shown.