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Petroleum Engineering 406 Lesson 18 Directional Drilling

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Petroleum Engineering 406 Lesson 18 Directional Drilling

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    1. Petroleum Engineering 406 Lesson 18 Directional Drilling

    3. Homework: READ. Applied Drilling Engineering Ch. 8, pp. 351-363 REF. API Bulletin D20, Directional Drilling Survey Calculation Methods and Terminology

    4. What is Directional Drilling? Directional Drilling is the process of directing a wellbore along some trajectory to a predetermined target. Basically it refers to drilling in a non-vertical direction. Even vertical hole sometimes require directional drilling techniques.

    14. Build Section:

    17. Fig. 8-14. Directional well used to intersect multiple targets

    18. Fig. 8-15. Directional quadrants and compass measurements

    20. Example 1: Design of Directional Well Design a directional well with the following restrictions: Total horizontal departure = 4,500 ft True vertical depth (TVD) = 12,500 ft Depth to kickoff point (KOP) = 2,500 ft Rate of build of hole angle = 1.5 deg/100 ft

    21. Example 1: Design of Directional Well This is a Type I well (build and hold) (i) Determine the maximum hole angle (inclination) required. (ii) What is the total measured depth of the hole (MD)?

    25. Solution Type I Well 1.5 deg/100

    26. Build Section MD1 = 1,800 (27/1.5) TVD1 = 1,734 HD1 = 416 Remaining vertical height = 10,000 - 1,734 = 8,266

    27. Solution Horizontally: 416 + 8,266 tan 27o = 4,628 We need 4,500 only: Next try Imax = 25 30 min

    28. Solution: Remaining vertical depth = 10,000-1644 = 8,356 ft. ? Horizontal deviation = 372+8,356 tan 25.5 = 4,358 ft. { ?4500 } Approx. maximum angle = 26 What is the size of target?

    29. MD = MDvert + MDbuild + MDhold

    30. Type II Pattern Given: KOP = 2,000 feet TVD = 10,000 feet Horiz. Depart. = 2,258 feet Build Rate = 20 per 100 feet Drop Rate = 10 30 per 100 feet The first part of the calculation is the same as previously described.

    31. Procedure - Find: a) The usable depth (8,000 feet) b) Maximum angle at completion of buildup (180) c) Measured depth and vertical depth at completion of build up (M.D.=900 ft. and TVD = 886) d) Measured depth, horizontal departure and TVD for 1 /100 ft from chart.

    32. Solve: For the distances corresponding to the sides of the triangle in the middle. Add up the results. If not close enough, try a different value for the maximum inclination angle, Imax

    33. Example 1: Design of Directional Well (i) Determine the maximum hole angle required. (ii) What is the total measured depth (MD)? (MD = well depth measured along the wellbore, not the vertical depth)

    34. (i) Maximum Inclination Angle

    35. (i) Maximum Inclination Angle

    36. (ii) Measured Depth of Well

    37. (ii) Measured Depth of Well

    38. We may plan a 2-D well, but we always get a 3D well (not all in one plane)

    39. Fig. 8-22. A curve representing a wellbore between survey stations A1 and A2

    40. Directional Drilling 1. Drill the vertical (upper) section of the hole. 2. Select the proper tools for kicking off to a non-vertical direction 3. Build angle gradually

    41. Directional Tools (i) Whipstock (ii) Jet Bits (iii) Downhole motor and bent sub

    42. Whipstocks

    43. Setting a Whipstock Small bit used to start Apply weight to: set chisel point & shear pin Drill 12-20 Remove whipstock Enlarge hole

    44. Jetting Bit Fast and economical For soft formation One large - two small nozzles Orient large nozzle Spud periodically No rotation at first

    45. Jetting Wash out pocket Return to normal drilling Survey Repeat for more angle if needed

    46. Mud Motors

    48. Increasing Inclination Limber assembly Near bit stabilizer Weight on bit forces DC to bend to low side of hole. Bit face kicks up

    49. Hold Inclination Packed hole assembly Stiff assembly Control bit weight and RPM

    50. Decrease Inclination Pendulum effect Gravity pulls bit downward No near bit stabilizer

    51. Packed Hole Assemblies

    54. Deflecting Wellbore Trajectory

    55. Bottom Hole Location

    56. Survey Calculation Methods 1. Tangential Method = Backward Station Method = Terminal Angle Method Assumption: Hole will maintain constant inclination and azimuth angles between survey points

    58. Average Angle Method = Angle Averaging Method Assumption: Borehole is parallel to the simple average drift and bearing angles between any two stations. Known: Location of A, Distance AB, Angles

    59. (i) Simple enough for field use (ii) Much more accurate than Tangential Method

    60. Average Angle Method Vertical Plane:

    61. Average Angle Method Horizontal Plane:

    62. Change in position towards the east: Change in position towards the north:

    63. Example The coordinates of a point in a wellbore are: x = 1000 ft (easting) y = 2000 ft (northing) z = 3000 ft (depth) At this point (station) a wellbore survey shows that the inclination is 15 degrees from vertical, and the direction is 45 degrees east of north. The measured distance between this station and the next is 300 ft.

    64. Example The coordinates of point 1 are: x1 = 1000 ft (easting) y1 = 2000 ft (northing) I1 = 15o z1 = 3000 ft (depth) A1 = 45o L12 = 300 ft At point 2, I2 = 25o and A2 = 65o Find x2 , y2 and z2

    65. Solution H12 = L12 sin Iavg = 300 sin 20 = 103 ft DE = H12 sin Aavg = 103 sin 55 = 84 ft DN = H12 cos Aavg = 103 cos 55 = 59 ft DZ = L12 cos Iavg = 300 cos 20 = 282 ft

    66. Solution - contd DE = 84 ft DN = 59 ft DZ = 282 ft x2 = x1 + DE = 1,000 + 84 ft = 1,084 ft y2 = y1 + DN = 2,000 + 59 ft = 2,059 ft z2 = z1 + DZ = 3,000 + 282 ft = 3,282 ft

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