1 / 7

Free Body Diagram of Cable-Pulley System

Free Body Diagram of Cable-Pulley System. T AC. y. T AC = The tension FROM the supporting cable (at 30 º) ON the pulley. x. 30 º. Θ. T = The tension holding the system in equilibrium (at angle Θ ) ON the pulley. W B. T. W B = Weight of Ball B ON the pulley.

acrum
Télécharger la présentation

Free Body Diagram of Cable-Pulley System

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Free Body Diagram of Cable-Pulley System TAC y TAC= The tension FROM the supporting cable (at 30º) ON the pulley. x 30º Θ T= The tension holding the system in equilibrium (at angle Θ) ON the pulley. WB T WB= Weight of Ball B ON the pulley. *Click for next example C The system is held in equilibrium at angle Θ by the tension, T. A cable connects pulley A to the ceiling at point C. Ignore the weight of the pulley and the cable. 30º *Click to see solutions A Θ T B FBD of pulley A A

  2. Free Body Diagram of Suspended Man R1 R1= Reaction force FROM rope ON man T1 y T1= Tension FROM rope ON man x W W = Weight of man *Click for next example The man is sliding across the rope on a bar and being pulled by the tension T. Ignore any frictional effects. *Treat the man and bar as one object FBD of Man T1 *Click to see solutions

  3. Free Body Diagram of Beam With Applied Moment and Force F = The applied force ON the beam. F RB = The reaction force FROM ground point B ON the beam RA = The reaction force FROM ground point A ON the beam M M = The applied moment on the beam. RA RB *Click for next example F The beam at rest has an applied moment, M, and an applied Force, F. It is resting on two I-beams at A and B. Ignore the weight of the beam. I I B A M *Click to see solutions FBD of Beam

  4. Free Body Diagram of Multiple Pulley-Cable System e c d a b F F B 1 2 A Block A is supported by the pulley system shown. The force, F, is pulling the rope downward. Ignore the weight of the pulleys. *Click to see solutions

  5. Free Body Diagram of Multiple Pulley-Cable System Tc = Tension FROM cable ON pulley B. R1 = Reaction force ON block A FROM support 1. Td = Tension FROM cable ON pulley B. R2 = Reaction force ON block A FROM support 2. R2 = Reaction force FROM support 2 ON pulley B. W = Weight of block A. y Tc Td R1 R2 x W *Click for next example R2 e c d b a F F B 2 1 A *Click to see solutions Free body diagram of the block Free body diagram of the pulley at B A B

  6. Free Body Diagram of Multiple-Spring System y x T1= Tension FROM spring 1 ON block A T1 T2 = Tension FROM spring 2 ON ball B T2 WB= Weight of block B T2 WA T2 = Tension FROM spring 2 ON block A WB WA = Weight of block A *Click for next example 1 The system is at rest. A 2 B *Click to see solutions FBD of Block A FBD of Ball B A B

  7. Free Body Diagram of Beam Resting on Angled Surfaces F F = The applied force ON the beam. F The beam is resting on two smooth surfaces. There is an applied force, F, and a tension, T, on the rope. B A 30º 60º *Click to see solutions FBD of Beam T RB = The reaction force FROM ground point B ON the beam Original surface Original surface 30º 30º 60º 60º RA = The reaction force FROM ground point A ON the beam RB T RA W T = The tension force FROM the rope ON the beam. W = Weight of the beam *Click for next example

More Related